Roy*_*mir 10 xml sql t-sql sql-server sql-server-2005
我有这个xml:
DECLARE @x XML
SET @x =
'<data>
<add>a</add>
<add>b</add>
<add>c</add>
</data>';
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任务:
我想列出一下 a,b,c.
方法1:
SELECT s.value('.', 'VARCHAR(8000)') AS [ADD]
FROM @x.nodes('/data/add') AS t(s)
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方法2:
DECLARE @idoc INT
EXEC sp_xml_preparedocument @idoc OUTPUT, @x
SELECT *
FROM OPENXML(@idoc, '/data/add', 2)
WITH ([add] NVARCHAR(MAX) '.')
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他们俩都给我:

题 :
哪个是首选方式?
后者与前者(或反之)有什么好处吗?
一个简单的测试表明,您的方法1比方法2花费的时间更少.关于它总是如此,我不会得出任何结论.它可能取决于XML的结构以及查询XML的方式.
要测试的存储过程:
create procedure TestXML
@X xml
as
set nocount on
select X.N.value('.', 'varchar(8000)')
from @X.nodes('/root/item') as X(N)
go
create procedure TestOpenXML
@X xml
as
set nocount on
declare @idoc int
exec sp_xml_preparedocument @idoc out, @X
select value
from openxml(@idoc, '/root/item',1)
with (value varchar(8000) '.')
exec sp_xml_removedocument @idoc
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测试:
declare @X xml
set @X =
(
select number as '*'
from master..spt_values
for xml path('item'), root('root'), type
)
set statistics time on
exec TestXML @X
exec TestOpenXML @X
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结果方法1:
SQL Server Execution Times:
CPU time = 63 ms, elapsed time = 70 ms.
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结果方法2:
SQL Server Execution Times:
CPU time = 156 ms, elapsed time = 159 ms.
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(在SQL Server 2005上测试过.)
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