gma*_*mus 18 sql sql-server-2008
X Y DATE
1 20 20120101
1 21 20120101
2 30 20120201
3 40 20120201
3 41 20120301
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我想选择具有X相同的另一行的任何行,但日期不同,即答案是
3 40 20120201
3 41 20120301
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Yuc*_*uck 22
试试这个...
SELECT *
FROM YourTable
WHERE X IN (
SELECT T1.X
FROM YourTable T1 INNER JOIN
YourTable T2 ON T1.X = T2.X
WHERE T1.DATE <> T2.DATE
);
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这应该适用于大多数符合ANSI标准的数据库产品.