获取文件扩展名

Question

我正在爆炸"." 获取文件格式和名称:

list($txt, $ext) = explode(".", $name);

问题是某些文件的名称带有点.

我如何在最后一次探索"." 所以我得到$name=pic.n2和$ext=jpg来自:pic.n2.jpg？

Answer 1

使用pathinfo:

$pi = pathinfo($name);
$txt = $pi['filename'];
$ext = $pi['extension'];

Answer 2

$name = pathinfo($file, PATHINFO_FILENAME);
$ext  = pathinfo($file, PATHINFO_EXTENSION);

http://www.php.net/pathinfo

Answer 3

用这个

$array = explode(".", $name);
end($array);         // move the internal pointer to the end of the array
$filetype = current($array);

谢谢