在PIL中打开图像文件时出错

Question

我正在尝试执行以下代码

from pytesser import *
import Image

i="C:/Documents and Settings/Administrator/Desktop/attachments/R1PNDTCB.jpg"
print i
im = Image.open(i.strip())
text = image_to_string(im)
print text

我收到以下错误

C:/Documents and Settings/Administrator/Desktop/attachments/R1PNDTCB.jpg
Traceback (most recent call last):
  File "C:\Python27\Lib\site-packages\Pythonwin\pywin\framework\scriptutils.py", line 322, in RunScript
    debugger.run(codeObject, __main__.__dict__, start_stepping=0)
  File "C:\Python27\Lib\site-packages\Pythonwin\pywin\debugger\__init__.py", line 60, in run
    _GetCurrentDebugger().run(cmd, globals,locals, start_stepping)
  File "C:\Python27\Lib\site-packages\Pythonwin\pywin\debugger\debugger.py", line 655, in run
    exec cmd in globals, locals
  File "C:\Documents and Settings\Administrator\Desktop\attachments\ocr.py", line 1, in <module>
    from pytesser import *
  File "C:\Python27\lib\site-packages\PIL\Image.py", line 1952, in open
    fp = __builtin__.open(fp, "rb")
IOError: [Errno 2] No such file or directory: 'C:/Documents and Settings/Administrator/Desktop/attachments/R1PNDTCB.jpg'

有人可以解释我在这里做错了什么.

重命名图像文件.将python文件和图像移动到新文件夹.将文件夹移至E盘现在代码如下:

from pytesser import *
import Image
import os

i=os.path.join("E:\\","ocr","a.jpg")
print i
im = Image.open(i.strip())
text = image_to_string(im)
print text

现在错误如下:

E:\ocr\a.jpg
Traceback (most recent call last):
  File "or.py", line 8, in <module>
    text = image_to_string(im)
  File "C:\Python27\lib\pytesser.py", line 31, in image_to_string
    call_tesseract(scratch_image_name, scratch_text_name_root)
  File "C:\Python27\lib\pytesser.py", line 21, in call_tesseract
    proc = subprocess.Popen(args)
  File "C:\Python27\lib\subprocess.py", line 679, in __init__
    errread, errwrite)
  File "C:\Python27\lib\subprocess.py", line 893, in _execute_child
    startupinfo)
WindowsError: [Error 2] The system cannot find the file specified

Answer 1

例外情况非常明显：该文件要么不存在，要么您没有足够的权限来访问它。如果不是这种情况，请提供证据（例如dir带有输出的相关命令，以同一用户身份运行）。