添加一周到Date()

Question

如何将1周添加到具有单独日期变量的日期函数中.日期需要分开,以便我可以将其插入另一种形式.如果我不能将它作为单独的变量,我之后可以将它们分开吗？

所以:

$year = date("Y");
$month = date("m");
$day = date("d");
echo 'Current Date' . $year . '.' . $month . '.' . $day;
echo 'Date 1 Week in the Future';

Answer 1

用途strtotime:

echo "Date 1 Week in the Future " . date('Y.m.d', strtotime('+1 Week'));
// Outputs: Date 1 Week in the Future 2012.03.10

要分解为单独的变量(根据您的评论):

$oneWeekLater = strtotime('+1 Week');

$year = date('Y', $oneWeekLater);
$month = date('m', $oneWeekLater);
$day = date('d', $oneWeekLater);

echo 'Date 1 Week in the Future' . $year . '.' . $month . '.' . $day;

Answer 2

PHP提供了方便的strtotime方法:

$oneWeekLater = date('Y.m.d', strtotime('+1 week'));

要传递自定义日期,请使用strtotime第二个参数.