Android:缩小字体大小后,TextView高度不会改变

Question

当我单击按钮时,字体大小缩小为12.但结果是:

main.xml中

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:orientation="vertical" >

    <TextView
        android:id="@+id/test"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:textSize="40sp"
        android:background="#80ff0000"
        android:text="@string/hello" />

    <Button
        android:id="@+id/button1"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="Button" />

</LinearLayout>

Java的:

public class FontSizeTestActivity extends Activity {
    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.main);
        final TextView text = (TextView) findViewById(R.id.test);




        Button button1 = (Button) findViewById(R.id.button1);
        button1.setOnClickListener(new View.OnClickListener() {

            public void onClick(View v) {

                text.setTextSize(12);
            }
        });
    }
}

如何缩小textView的高度,使其仅包装实际字体？

Answer 1

所以,经过长时间的搜索,我找到了解决方案.每次设置文本时都执行:

setText("I am a Text",TextView.BufferType.SPANNABLE);

或者在调整文本大小后,只需:

setText(getText(),TextView.BufferType.SPANNABLE);

Answer 2

最后,我找到了原因/解决方案!

这是Android 3.1+的已知错误

问题17343

问题22493

可能的解决方法是:

text.setText(text+"\n");

要么

final String DOUBLE_BYTE_SPACE = "\u3000";
text.setText(text + DOUBLE_BYTE_SPACE);

Answer 3

而不是使用:

final String DOUBLE_BYTE_SPACE = "\u3000";
text.setText(text + DOUBLE_BYTE_SPACE);

更好用:

final String DOUBLE_BYTE_WORDJOINER = "\u2060";
text.setText(text + DOUBLE_BYTE_WORDJOINER);

额外信息:Word Joiner是0宽度空间.