Ste*_*fan 59 python python-2.7
我想将一个字符串保存到一个名为python程序的文件中 Failed.py
这是我到目前为止:
myFile = open('today','r')
ips = {}
for line in myFile:
parts = line.split(' ')
if parts[1] == 'Failure':
if parts[0] in ips:
ips[pars[0]] += 1
else:
ips[parts[0]] = 0
for ip in [k for k, v in ips.iteritems() if v >=5]:
#write to file called Failed.py
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war*_*iuc 145
file = open('Failed.py', 'w')
file.write('whatever')
file.close()
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这是一个更pythonic版本,它会自动关闭文件,即使包装块中有异常:
with open('Failed.py', 'w') as file:
file.write('whatever')
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Dav*_*nan 18
您需要再次使用打开文件open()
,但这次传递'w'
表示您要写入文件.我还建议您使用with
以确保在写完文件后关闭该文件.
with open('Failed.txt', 'w') as f:
for ip in [k for k, v in ips.iteritems() if v >=5]:
f.write(ip)
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当然,您可能希望在输出中包含换行符或其他格式,但基本操作如上所述.
关闭文件的相同问题适用于阅读代码.这应该是这样的:
ips = {}
with open('today','r') as myFile:
for line in myFile:
parts = line.split(' ')
if parts[1] == 'Failure':
if parts[0] in ips:
ips[pars[0]] += 1
else:
ips[parts[0]] = 0
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