我正在尝试自动化MySQL用户创建过程.我想创建一个包含mysql用户创建语句的临时文件,然后我会这样调用它:
mysql -u root -proot <temp
但我坚持使用mysql语法:这是我的临时文件的内容:
DROP DATABASE IF EXISTS mytestdatabase;
CREATE DATABASE mytestdatabase;
SELECT @password:="my password";
DELETE FROM mysql.user WHERE Host='localhost' AND User='mytestdatabase';
GRANT ALL PRIVILEGES ON mytestdatabase.* TO 'mytestdatabase'@'localhost' IDENTIFIED BY PASSWORD '@password';
FLUSH PRIVILEGES;
但行
GRANT ALL PRIVILEGES ON mytestdatabase.* TO 'mytestdatabase'@'localhost' IDENTIFIED BY PASSWORD '@password';
(密码哈希值应为41位十六进制数)
并没有被解释为我所期望的那样.即使我删除@password标记周围的单引号,我仍然有错误(语法错误)
我怎样才能做到这一点?
eye*_*hUp 54
只是为了回答错误发生的原因并显示差异:
@password是哈希字符串1值:
GRANT ALL PRIVILEGES 
    ON `mydb` . * TO 'username'@'localhost' IDENTIFIED 
BY
PASSWORD '@password';
注意使用PASSWORD关键字!
@password是明文字符串值:  
GRANT ALL PRIVILEGES 
    ON `mydb` . * TO 'username'@'localhost' IDENTIFIED 
BY
'@password';
注意缺少的 PASSWORD关键字!
SELECT PASSWORD('clearTextPasswd');- 请参阅雪人的答案.
        Dev*_*art 11
如果您不想以明文形式存储密码,请将其保存为散列格式 -
GRANT ALL PRIVILEGES ON mytestdatabase.* TO 'mytestdatabase'@'localhost'
  IDENTIFIED BY PASSWORD '*7560636C2922C05954FE6A2446AA00C84708B57B';
散列密码是此查询的结果 -
SELECT PASSWORD('my password');
小智 5
查看以下网址,这将帮助您解决问题:
http://linuxadministrator.pro/blog/?p=147
mysql> select password('12345');
+-------------------------+
| password('123456') |
+-------------------------+
| 2ff898e158cd0311        |
+-------------------------+
1 row in set (0.00 sec)
mysql> create user test identified by password '2ff898e158cd0311';
Query OK, 0 rows affected (0.00 sec)