如何在Python中通过索引从列表中删除n个元素？

Question

我们假设,

g = ['1', '', '2', '', '3', '', '4', '']

我想''从g中删除所有,我必须得到

g = ['1', '2', '3', '4']

Answer 1

>>> g = ['1', '', '2', '', '3', '', '4', '']
>>> filter(None, g)
['1', '2', '3', '4']

Help on built-in function filter in module `__builtin__`:

filter(...)
filter(function or None, sequence) -> list, tuple, or string

   Return those items of sequence for which function(item) is true.  If
   function is None, return the items that are true.  If sequence is a tuple
   or string, return the same type, else return a list.

如果您愿意,也可以使用列表推导

>>> [x for x in g if x!=""]
['1', '2', '3', '4']

Answer 2

如果列表是所有字符串,请在if语句中使用空序列为false的事实:

>>> g = ['1', '', '2', '', '3', '', '4', '']
>>> [x for x in g if x]
['1', '2', '3', '4']

否则,请使用 [x for x in g if x != '']