我有以下功能
ALTER FUNCTION [dbo].[ActualWeightDIMS]
(
-- Add the parameters for the function here
@ActualWeight int,
@Actual_Dims_Lenght int,
@Actual_Dims_Width int,
@Actual_Dims_Height int
)
RETURNS varchar(50)
AS
BEGIN
DECLARE @ActualWeightDIMS varchar(50);
--Actual Weight
IF (@ActualWeight is not null)
SET @ActualWeightDIMS = @ActualWeight;
--Actual DIMS
IF (@Actual_Dims_Lenght is not null) AND
(@Actual_Dims_Width is not null) AND (@Actual_Dims_Height is not null)
SET @ActualWeightDIMS= @Actual_Dims_Lenght + 'x' + @Actual_Dims_Width + 'x' + @Actual_Dims_Height;
RETURN(@ActualWeightDIMS);
END
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但当我尝试使用它时,我收到以下错误"将varchar值'x'转换为数据类型int时转换失败." 当我使用以下select语句时
select
BA_Adjustment_Detail.ID_Number [ID_Number],
BA_Adjustment_Detail.Submit_Date [Submit_Date],
BA_Category.Category [category],
BA_Type_Of_Request.Request [Type_Of_Request],
dbo.ActualWeightDIMS(BA_Adjustment_Detail.ActualWeight,BA_Adjustment_Detail.Actual_Dims_Lenght,BA_Adjustment_Detail.Actual_Dims_Width,BA_Adjustment_Detail.Actual_Dims_Height) [Actual Weight/DIMS],
BA_Adjustment_Detail.Notes [Notes],
BA_Adjustment_Detail.UPSCustomerNo [UPSNo],
BA_Adjustment_Detail.TrackingNo [AirbillNo],
BA_Adjustment_Detail.StoreNo [StoreNo],
BA_Adjustment_Detail.Download_Date [Download_Date],
BA_Adjustment_Detail.Shipment_Date[ShipmentDate],
BA_Adjustment_Detail.FranchiseNo [FranchiseNo],
BA_Adjustment_Detail.CustomerNo [CustomerNo],
BA_Adjustment_Detail.BillTo [BillTo],
BA_Adjustment_Detail.Adjustment_Amount_Requested [Adjustment_Amount_Requested]
from BA_Adjustment_Detail
inner join BA_Category
on BA_Category.ID = BA_Adjustment_Detail.CategoryID
inner join BA_Type_Of_Request
on BA_Type_Of_Request.ID = BA_Adjustment_Detail.TypeOfRequestID
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我想要做的是,如果ActualWeight不为null,则返回ActualWeight为"Actual Weight/DIMS",否则使用Actual_Dims_Lenght,Width和Height.
如果是DIMS,那么我想将输出格式化为LenghtxWidhtxHeight(15x10x4).ActualWeight,Adcutal_Dims_Lenght,Width和Height都是int(整数)值,但"Actual Weight/DIMS"的输出应为varchar(50).
我在哪里弄错了?
谢谢
编辑:用户只能在ASP.net页面上选择Weight或DIMS,如果用户选择了DIMS,那么他们必须提供Length,Width和Height.否则它将在ASP.net页面上抛出错误.我应该在sql方面担心吗?
Tom*_*m H 195
几个快速笔记:
现在解决问题......
在尝试连接它们之前,需要将参数显式转换为VARCHAR.当SQL Server看到@my_int +'X'时,它认为您正在尝试将数字"X"添加到@my_int,但它无法执行此操作.而是尝试:
SET @ActualWeightDIMS =
CAST(@Actual_Dims_Lenght AS VARCHAR(16)) + 'x' +
CAST(@Actual_Dims_Width AS VARCHAR(16)) + 'x' +
CAST(@Actual_Dims_Height AS VARCHAR(16))
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Pரத*_*ீப் 47
如果您使用的是SQL Server 2012+,则可以使用CONCAT函数,我们无需进行任何显式转换
SET @ActualWeightDIMS = Concat(@Actual_Dims_Lenght, 'x', @Actual_Dims_Width, 'x'
, @Actual_Dims_Height)
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改变这个:
SET @ActualWeightDIMS= @Actual_Dims_Lenght + 'x' +
@Actual_Dims_Width + 'x' + @Actual_Dims_Height;
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对此:
SET @ActualWeightDIMS= CAST(@Actual_Dims_Lenght as varchar(3)) + 'x' +
CAST(@Actual_Dims_Width as varchar(3)) + 'x' +
CAST(@Actual_Dims_Height as varchar(3));
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改变这个:
SET @ActualWeightDIMS = @ActualWeight;
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对此:
SET @ActualWeightDIMS = CAST(@ActualWeight as varchar(50));
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您需要使用CAST.在这里了解CAST和CONVERT的所有内容,因为数据类型很重要!
select 'abcd' + ltrim(str(1)) + ltrim(str(2))
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