Web服务没有添加引用？

Question

我有3个Web服务添加到类库中的服务引用.(这是一个API使用的示例项目)我需要将它们移动到我的项目中但由于安全问题我无法添加服务引用(安全问题我意味着服务只响应一个IP地址,这是我们客户服务器的IP地址.)是否有办法为该particaluar Web服务生成类似于使用"Ildasm.exe"的类？

Answer 1

你可以使用这个类.我不记得我在哪里找到了基本代码,我之前添加了一些方法并转换为类.

public class WebService
{
    public string Url { get; set; }
    public string MethodName { get; set; }
    public Dictionary<string, string> Params = new Dictionary<string, string>();
    public XDocument ResultXML;
    public string ResultString;

    public WebService()
    {

    }

    public WebService(string url, string methodName)
    {
        Url = url;
        MethodName = methodName;
    }

    /// <summary>
    /// Invokes service
    /// </summary>
    public void Invoke()
    {
        Invoke(true);
    }

    /// <summary>
    /// Invokes service
    /// </summary>
    /// <param name="encode">Added parameters will encode? (default: true)</param>
    public void Invoke(bool encode)
    {
        string soapStr =
            @"<?xml version=""1.0"" encoding=""utf-8""?>
            <soap:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" 
               xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" 
               xmlns:soap=""http://schemas.xmlsoap.org/soap/envelope/"">
              <soap:Body>
                <{0} xmlns=""http://tempuri.org/"">
                  {1}
                </{0}>
              </soap:Body>
            </soap:Envelope>";

        HttpWebRequest req = (HttpWebRequest)WebRequest.Create(Url);
        req.Headers.Add("SOAPAction", "\"http://tempuri.org/" + MethodName + "\"");
        req.ContentType = "text/xml;charset=\"utf-8\"";
        req.Accept = "text/xml";
        req.Method = "POST";

        using (Stream stm = req.GetRequestStream())
        {
            string postValues = "";
            foreach (var param in Params)
            {
                if (encode)
                    postValues += string.Format("<{0}>{1}</{0}>", HttpUtility.UrlEncode(param.Key), HttpUtility.UrlEncode(param.Value));
                else
                    postValues += string.Format("<{0}>{1}</{0}>", param.Key, param.Value);
            }

            soapStr = string.Format(soapStr, MethodName, postValues);
            using (StreamWriter stmw = new StreamWriter(stm))
            {
                stmw.Write(soapStr);
            }
        }

        using (StreamReader responseReader = new StreamReader(req.GetResponse().GetResponseStream()))
        {
            string result = responseReader.ReadToEnd();
            ResultXML = XDocument.Parse(result);
            ResultString = result;
        }
    }
}

你可以像这样使用

WebService ws = new WebService("service_url", "method_name");
ws.Params.Add("param1", "value_1");
ws.Params.Add("param2", "value_2");
ws.Invoke();
// you can get result ws.ResultXML or ws.ResultString

Answer 2

您无需添加Web服务引用即可使用Web服务代码:您可以手动生成要使用的类,例如:

wsdl.exe /out:d:/Proxy.cs/order http:// localhost:2178/Services.asmx

然后,您可以手动将此文件添加到项目中.