Jud*_*ngo 19 c# algorithm hierarchy hierarchical-data
我有一个看起来像这样的文本文件:
{ Id = 1, ParentId = 0, Position = 0, Title = "root" }
{ Id = 2, ParentId = 1, Position = 0, Title = "child 1" }
{ Id = 3, ParentId = 1, Position = 1, Title = "child 2" }
{ Id = 4, ParentId = 1, Position = 2, Title = "child 3" }
{ Id = 5, ParentId = 4, Position = 0, Title = "grandchild 1" }
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我正在寻找一种通用的C#算法,它将从中创建一个对象层次结构.如果您愿意,可以使用"层次结构"功能将此数据转换为对象层次结构.
有任何想法吗?
编辑我已经将文件解析为.NET对象:
class Node
{
public int Id { get; }
public int ParentId { get; }
public int Position { get; }
public string Title { get; }
}
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现在我需要将对象实际排列到对象图中.
Jud*_*ngo 24
非常感谢Jon和mquander - 你们给了我足够的信息来帮助我以正确的,通用的方式解决这个问题.这是我的解决方案,一个将对象转换为层次结构形式的通用扩展方法:
public static IEnumerable<Node<T>> Hierarchize<T, TKey, TOrderKey>(
this IEnumerable<T> elements,
TKey topMostKey,
Func<T, TKey> keySelector,
Func<T, TKey> parentKeySelector,
Func<T, TOrderKey> orderingKeySelector)
{
var families = elements.ToLookup(parentKeySelector);
var childrenFetcher = default(Func<TKey, IEnumerable<Node<T>>>);
childrenFetcher = parentId => families[parentId]
.OrderBy(orderingKeySelector)
.Select(x => new Node<T>(x, childrenFetcher(keySelector(x))));
return childrenFetcher(topMostKey);
}
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利用这个小节点类:
public class Node<T>
{
public T Value { get; private set; }
public IList<Node<T>> Children { get; private set; }
public Node(T value, IEnumerable<Node<T>> children)
{
this.Value = value;
this.Children = new List<Node<T>>(children);
}
}
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它足够通用,可以解决各种问题,包括我的文本文件问题.漂亮!
****更新****:以下是你如何使用它:
// Given some example data:
var items = new[]
{
new Foo()
{
Id = 1,
ParentId = -1, // Indicates no parent
Position = 0
},
new Foo()
{
Id = 2,
ParentId = 1,
Position = 0
},
new Foo()
{
Id = 3,
ParentId = 1,
Position = 1
}
};
// Turn it into a hierarchy!
// We'll get back a list of Node<T> containing the root nodes.
// Each node will have a list of child nodes.
var hierarchy = items.Hierarchize(
-1, // The "root level" key. We're using -1 to indicate root level.
f => f.Id, // The ID property on your object
f => f.ParentId, // The property on your object that points to its parent
f => f.Position, // The property on your object that specifies the order within its parent
);
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嗯......我不太明白这是怎么回事.2和5如何都有parent = 1,position = 0?5个父母应该有2个,3个还是4个?
好的,这个新版本经历了三次所有节点:
它没有很好的封装,很好的错误检查等 - 但它的工作原理.
using System;
using System.Collections.Generic;
using System.IO;
public class Node
{
private static readonly char[] Braces = "{}".ToCharArray();
private static readonly char[] StringTrim = "\" ".ToCharArray();
public Node Parent { get; set; }
public int ParentId { get; private set; }
public int Id { get; private set; }
public string Title { get; private set; }
public int Position { get; private set; }
private readonly List<Node> children = new List<Node>();
public List<Node> Children { get { return children; } }
public static Node FromLine(string line)
{
Node node = new Node();
line = line.Trim(Braces);
string[] bits = line.Split(',');
foreach (string bit in bits)
{
string[] keyValue = bit.Split('=');
string key = keyValue[0].Trim();
string value = keyValue[1].Trim();
switch (key)
{
case "Id":
node.Id = int.Parse(value);
break;
case "ParentId":
node.ParentId = int.Parse(value);
break;
case "Position":
node.Position = int.Parse(value);
break;
case "Title":
node.Title = value.Trim(StringTrim);
break;
default:
throw new ArgumentException("Bad line: " + line);
}
}
return node;
}
public void Dump()
{
int depth = 0;
Node node = this;
while (node.Parent != null)
{
depth++;
node = node.Parent;
}
Console.WriteLine(new string(' ', depth * 2) + Title);
foreach (Node child in Children)
{
child.Dump();
}
}
}
class Test
{
static void Main(string[] args)
{
var dictionary = new Dictionary<int, Node>();
using (TextReader reader = File.OpenText("test.txt"))
{
string line;
while ((line = reader.ReadLine()) != null)
{
Node node = Node.FromLine(line);
dictionary[node.Id] = node;
}
}
foreach (Node node in dictionary.Values)
{
if (node.ParentId != 0)
{
node.Parent = dictionary[node.ParentId];
node.Parent.Children.Add(node);
}
}
foreach (Node node in dictionary.Values)
{
node.Children.Sort((n1, n2) =>
n1.Position.CompareTo(n2.Position));
}
Node root = dictionary[1];
root.Dump();
}
}
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示例文本文件:
{ Id = 5, ParentId = 4, Position = 0, Title = "grandchild 1" }
{ Id = 2, ParentId = 1, Position = 0, Title = "child 1" }
{ Id = 4, ParentId = 1, Position = 2, Title = "child 3" }
{ Id = 3, ParentId = 1, Position = 1, Title = "child 2" }
{ Id = 1, ParentId = 0, Position = 0, Title = "root" }
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输出:
root
child 1
child 2
child 3
grandchild 1
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