在类中加载config.php

Question

我想在类中加载配置文件.这是config.php的内容

<?php
$__error_reporting_level=1;
$server='localhost';
$user='root';
$password='';
$dbase='eauction';
?>

sql.php的内容

<?php
include ('config.php');
error_reporting($__error_reporting_level);

class sql
{
 function connect()
 {
  $connections = mysql_connect($server, $user,$password) or die ('Unabale to connect to the database');
  mysql_select_db($dbase) or die ('Unable to select database!');
  return;
 }

 function login($email, $pwd)
 {
  $this->connect();
  $result = $this->qry("SELECT uid,nameF FROM user WHERE email='".$email."' AND password='".$pwd."'");
  $row=mysql_fetch_array($result);
  if (mysql_num_rows($result)>0)
   return array($row[0],$row[1]);
  else
   return array(0,0);
 }
}
?>

我使用执行代码

include ('core/sql.php');
$obj = new sql;
$data=$obj->login($email,$pwd);
print_r($data);

我收到这个错误

无法选择数据库!

忽略mysql注入问题,我只需要完美地执行代码

Answer 1

为什么不使用.ini文件？

config.ini文件

server=test
user=root
pass=pass
dbname=mydb

在你的课堂上有类似的东西

class A {

    public $config;

    public function __construct() {
       $this->config = parse_ini_file('config.ini', true);
    }

    public function sql() {
        $connections = mysql_connect($this->config['server'], $this->config['user'],$this->config['password']) or die ('Unabale to connect to the database');
  mysql_select_db($this->config['dbase']) or die ('Unable to select database!');
  return;
    }
}

只是另一种方法,确保您的数据库也正确命名.

此外,如果要使用当前的config.php,则需要在使用变量的方法中包含.不能在该范围之外使用它.

function connect()
 {
    include ('config.php');
  $connections = mysql_connect($server, $user,$password) or die ('Unabale to connect to the database');
  mysql_select_db($dbase) or die ('Unable to select database!');
  return;
 }

Answer 2

阅读PHP手册中的变量范围。

您已经在类声明之前将文件包括在全局范围内，而类方法范围无法访问该文件。如果要在类方法中使用这些变量，则需要通过$GLOBALS[]或global关键字全局访问它们，或者更好的是，将它们传递给使用它们的函数。

include ('config.php');
// Now all your variables are defined at global scope!!!
error_reporting($__error_reporting_level);

class sql
{
 // Pass as params to the function
 function connect($server, $user, $password, $dbase)
 {
  $connections = mysql_connect($server, $user,$password) or die ('Unabale to connect to the database');
  mysql_select_db($dbase) or die ('Unable to select database!');
  return;
 }
 // etc...
 // etc...
}

您可能还考虑将它们设置为类属性，并将其传递给构造函数：

class sql
{
  public $server;
  public $user;
  public $password;
  public $dbase;

  public function __construct($server, $user, $password, $dbase) {
    $this->server = $server;
    $this->user = $user;
    // etc...
    $connections = mysql_connect($this->server, $this->user, $this->password);
  }
}