如何在python 3.x中使用string.replace()

Question

string.replace()在python 3.x上已弃用.这样做的新方法是什么？

Answer 1

与2.x一样,使用str.replace().

例:

>>> 'Hello world'.replace('world', 'Guido')
'Hello Guido'

另请注意,点绑定比字符串连接更强,即使用括号:('Hello'+'world').replace('world','Guido')

Answer 2

replace()是<class 'str'>python3中的一种方法:

>>> 'hello, world'.replace(',', ':')
'hello: world'

Answer 3

python 3中的replace（）方法仅用于：

a = "This is the island of istanbul"
print (a.replace("is" , "was" , 3))

#3 is the maximum replacement that can be done in the string#

>>> Thwas was the wasland of istanbul

# Last substring 'is' in istanbul is not replaced by was because maximum of 3 has already been reached

Answer 4

您可以使用str.replace（）作为链str.replace（） 。认为你有一个像这样的字符串'Testing PRI/Sec (#434242332;PP:432:133423846,335)'，你想'#',':',';','/'用'-'. 您可以通过这种方式（正常方式）替换它，

>>> string = 'Testing PRI/Sec (#434242332;PP:432:133423846,335)'
>>> string = string.replace('#', '-')
>>> string = string.replace(':', '-')
>>> string = string.replace(';', '-')
>>> string = string.replace('/', '-')
>>> string
'Testing PRI-Sec (-434242332-PP-432-133423846,335)'

或者这样（str.replace()链）

>>> string = 'Testing PRI/Sec (#434242332;PP:432:133423846,335)'.replace('#', '-').replace(':', '-').replace(';', '-').replace('/', '-')
>>> string
'Testing PRI-Sec (-434242332-PP-432-133423846,335)'

Answer 5

str.replace的官方文档Python 3

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官方文档：Python 3str.replace

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str.replace(旧的，新的[，计数])

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返回字符串的副本，其中所有出现的子字符串 old 都被 new 替换。如果给出了可选参数 count，则仅替换第一个出现的 count。

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相应的VSCode语法提示是：

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str.replace(self: str, 旧的, 新的, 计数) -> str

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两种使用方法str.replace

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• 方法1：使用内置str\的replace ->str.replace(strVariable, old, new[, count])
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replacedStr1 = str.replace(originStr, "from", "to")\n

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• 方法2：使用str变量替换->strVariable.replace(old, new[, count])
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replacedStr2 = originStr.replace("from", "to")\n

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完整演示

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代码：

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originStr = "Hello world"\n\n# Use case 1: use builtin str\'s replace -> str.replace(strVariable, old, new[, count])\nreplacedStr1 = str.replace(originStr, "world", "Crifan Li")\nprint("case 1: %s -> %s" % (originStr, replacedStr1))\n\n# Use case 2: use str variable\'s replace -> strVariable.replace(old, new[, count])\nreplacedStr2 = originStr.replace("world", "Crifan Li")\nprint("case 2: %s -> %s" % (originStr, replacedStr2))\n

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输出：

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case 1: Hello world -> Hello Crifan Li\ncase 2: Hello world -> Hello Crifan Li\n

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截屏：

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Answer 6

尝试这个：

mystring = "This Is A String"
print(mystring.replace("String","Text"))