ExtJS抓取JSON结果

Question

我正在从PHP女巫生成JSON响应,如下所示:

{ done:'1', options: [{ message:'Example message'},{message:'This is the 2nd example message'}]}

我想使用ExtJS获取这些结果.这是我到目前为止:

Ext.Ajax.request({
    loadMask: true,
    url: 'myfile.php',
    params: {id: "1"}
});

接下来我要写什么才能得到像这样的json结果:

var mymessages = jsonData.options;

mymessages应该包含Example消息,这是第二个示例消息.

谢谢.

Answer 1

直截了当的方法:

Ext.Ajax.request({
  loadMask: true,
  url: 'myfile.php',
  params: {id: "1"},
  success: function(resp) {
    // resp is the XmlHttpRequest object
    var options = Ext.decode(resp.responseText).options;

    Ext.each(options, function(op) {
      alert(op.message);
    }
  }
});

或者您可以使用Store以更多Ext-ish方式执行此操作:

var messages = new Ext.data.JsonStore({
  url: 'myfile.php',
  root: 'options',
  fields: [
    {name: 'text', mapping: 'message'}
  ],
  listeners: {
    load: messagesLoaded
  }
});
messages.load({params: {id: "1"}});

// and when loaded, you can take advantage of
// all the possibilities provided by Store
function messagesLoaded(messages) {
  messages.each(function(msg){
    alert(msg.get("text"));
  });
}

再一个例子来解决最后的评论:

var messages = [{title: "1"},{title: "2"},{title: "3"}];

var titles = msg;
Ext.each(messages, function(msg){
  titles.push(msg.title);
});
alert(titles.join(", "));

虽然我更喜欢使用Array.map(Ext不提供):

var text = messages.map(function(msg){
  return msg.title;
}).join(", ");
alert(text);

Answer 2

使用成功和失败属性:

Ext.Ajax.request({
    loadMask: true,
    url: 'myfile.php',
    params: {id: "1"},
    success: function(response, callOptions) {
       // Use the response
    },
    failure: function(response, callOptions) {
       // Use the response
    }
});

有关更多详细信息,请参阅Ext API文档