Fre*_*nck 7 sql sqlite cocoa-touch objective-c ios
我是SQLite的新手.我有一个UITableview包含不同的日子.(星期一至星期日).当我点击例如星期一时,另一个viewcontroller包含一个UITableview.在同一个viewcontroller我有一个UIButton当我点击它我可以添加数据到我的SQLite数据库[ A ],我插入名称和星期几(星期几是在这个例子'星期一'这是因为我点击星期一视图控制器).
当我插入一个名字时,它出现在我的tableview中.但是当我回到我的第一个视图控制器时,我在周三点击了例如我添加的数据也出现在那里.
所以我的问题是; 如何显示我在星期一插入的名称,仅在星期一的tableview中,而不是其他日子(tableviews)
更多信息:
因此,当用户在'星期一'添加名称时,我将带有添加名称的dayoftheweek发送到SQLite数据库,当用户在星期三添加名称时,我发送'dayoftheweek'星期三等.
数据库咖啡看起来像=
CoffeeName | dayoftheweek
-------------------------
Hello world | Monday
Hello Planet | Wednesday
Hello Animal | Monday
Hello STOVW | Friday
[一个] const char *sql = "insert into Coffee(CoffeeName, dayoftheweek) Values(?, ?)";
我需要检查一天(例如)星期一是否与dayoftheweek(星期一)相同,然后显示包含'dayoftheweek monday'的项目
我的sqlite看起来像:
+ (void) getInitialDataToDisplay:(NSString *)dbPath {
if (sqlite3_open([dbPath UTF8String], &database) == SQLITE_OK) {
const char *sql = "select coffeeID, coffeeName from coffee";
sqlite3_stmt *selectstmt;
if(sqlite3_prepare_v2(database, sql, -1, &selectstmt, NULL) == SQLITE_OK) {
while(sqlite3_step(selectstmt) == SQLITE_ROW) {
NSInteger primaryKey = sqlite3_column_int(selectstmt, 0);
Coffee *coffeeObj = [[Coffee alloc] initWithPrimaryKey:primaryKey];
coffeeObj.LessonName = [NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 1)];
coffeeObj.dayoftheweek = [NSString stringWithUTF8String:(char *)sqlite3_column_text(selectstmt, 1)];
coffeeObj.isDirty = NO;
[appDelegate.coffeeArray addObject:coffeeObj];
}
}
}
else
sqlite3_close(database); //Even though the open call failed, close the database connection to release all the memory.
}
- (void) addCoffee1 {
if(addStmt == nil) {
const char *sql = "insert into Coffee(CoffeeName, dayoftheweek) Values(?, ?)";
if(sqlite3_prepare_v2(database, sql, -1, &addStmt, NULL) != SQLITE_OK)
NSAssert1(0, @"Error while creating add statement. '%s'", sqlite3_errmsg(database));
}
sqlite3_bind_text(addStmt, 1, [dayoftheweek UTF8String], -1, SQLITE_TRANSIENT);
if(SQLITE_DONE != sqlite3_step(addStmt))
NSAssert1(0, @"Error while inserting data. '%s'", sqlite3_errmsg(database));
else
//SQLite provides a method to get the last primary key inserted by using sqlite3_last_insert_rowid
LesID = sqlite3_last_insert_rowid(database);
//Reset the add statement.
sqlite3_reset(addStmt);
}
插入:
coffeeObj.dayoftheweek = [NSString stringWithFormat:@"%@", dayoftheweek];
这个插入: monday tuesday wednesday thursday friday saturday or sunday
但是如何显示星期一tableview中星期一插入的数据和星期二控制器等周二插入的数据.
我试过了 ;
if([coffeeObj.dayoftheweek isEqualToString:@"Monday"]) {
cell.day.text = coffeeObj.LessonName;
} else {
}
显示:
- (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath {
static NSString *CustomCellIdentifier = @"DaycusViewController";
DaycusViewController *cell = (DaycusViewController *)[tableView dequeueReusableCellWithIdentifier: CustomCellIdentifier];
if (cell == nil) {
NSArray *nib = [[NSBundle mainBundle] loadNibNamed:@"DaycusViewController"
owner:self options:nil];
for (id oneObject in nib) if ([oneObject isKindOfClass:[DaycusViewController class]])
cell = (DaycusViewController *)oneObject;
}
//Get the object from the array.
Coffee *coffeeObj = [appDelegate.coffeeArray objectAtIndex:indexPath.row];
cell.Name.text = CoffeeObj.CoffeeID;
cell.Day.text = CoffeeObj.dayoftheweek;
//i tried this: (not working)
/*begin*/if([CoffeeObj.dayoftheweek isEqualToString:@"Monday"]){
// cell.Name.text = CoffeeObj.CoffeeID;
//cell.Day.text = CoffeeObj.dayoftheweek;
} else {
}
/* end */
//it need's to display in this example only things where dayoftheweek is monday but.
return cell;
}
调用函数getInitialDataToDisplay
//Copy database to the user's phone if needed.
[self copyDatabaseIfNeeded];
//Initialize the coffee array.
NSMutableArray *tempArray = [[NSMutableArray alloc] init];
self.coffeeArray = tempArray;
[tempArray release];
//Once the db is copied, get the initial data to display on the screen.
[Coffee getInitialDataToDisplay:[self getDBPath]];
很难理解你的问题，但我认为你可以更好地打开一个新项目并从核心数据开始。它很容易理解并且比 SQLite 更快。
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