我无法从mysql SELECT方法转移到PDO方法.我想迭代两次获取的数组,两次从第0行开始.在mysql中我会使用:
mysql_data_seek($result,0);
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使用PDO方法,我不知道如何完成同样的事情.下面的代码是我试图这样做的方式.第一个while循环工作正常但第二个while循环没有返回任何东西.有人可以告诉我哪里出错了吗?
$pdo = new PDO('mysql:host=' . $host . ';dbname='.$database, $username, $password);
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$stmt = $pdo->prepare('SELECT * FROM mytable WHERE active = 1 ORDER BY name ASC');
$stmt->setFetchMode(PDO::FETCH_ASSOC);
$stmt->execute();
while($row = $stmt->fetch())
{
//do something starting with row[0]
}
while($row = $stmt->fetch())
{
//do something else starting with row[0]
}
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谢谢你的帮助.
Mar*_*lln 25
将结果保存到数组,然后将该数组循环两次.
$pdo = new PDO('mysql:host=' . $host . ';dbname='.$database, $username, $password);
$pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$stmt = $pdo->prepare('SELECT * FROM mytable WHERE active = 1 ORDER BY name ASC');
$stmt->setFetchMode(PDO::FETCH_ASSOC);
$stmt->execute();
$rows = $stmt->fetchAll();
foreach ($rows as $r) {
// first run
}
foreach ($rows as $r) {
// seconds run
}
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根据php手册,也可以多次发出查询,如果使用PDO :: prepare()准备PDOStatement对象,则可以通过多次调用PDOStatement :: execute()来发出语句。因此您的代码将如下所示。
$stmt = $pdo->prepare('SELECT * FROM mytable WHERE active = 1 ORDER BY name ASC');
$stmt->setFetchMode(PDO::FETCH_ASSOC);
//First execute
$stmt->execute();
while($row = $stmt->fetch())
{
//do something starting with row[0]
}
//Second execute
$stmt->execute();
while($row = $stmt->fetch())
{
//do something else starting with row[0]
}
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来源:http : //php.net/manual/en/pdo.query.php
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