如何将此NetHack函数移植到Python？

Question

我正在尝试编写一个Python函数,它返回与游戏NetHack中相同的月相值.这可以在hacklib.c中找到.

我试图简单地从NetHack代码中复制相应的函数,但我不相信我得到了正确的结果.

我写的功能是phase_of_the_moon().

功能position()和phase(),我在网上找到,我用它们作为我的功能成功的指示.它们非常准确,结果与nethack.alt.org服务器大致相符(请参阅http://alt.org/nethack/moon/pom.txt).然而,我所追求的是原始NetHack函数的精确复制,特性完整无缺.

我希望我的功能和'控制'功能至少给出相同的月相,但目前他们没有,我不知道为什么!

这是NetHack代码:

/*
 * moon period = 29.53058 days ~= 30, year = 365.2422 days
 * days moon phase advances on first day of year compared to preceding year
 *  = 365.2422 - 12*29.53058 ~= 11
 * years in Metonic cycle (time until same phases fall on the same days of
 *  the month) = 18.6 ~= 19
 * moon phase on first day of year (epact) ~= (11*(year%19) + 29) % 30
 *  (29 as initial condition)
 * current phase in days = first day phase + days elapsed in year
 * 6 moons ~= 177 days
 * 177 ~= 8 reported phases * 22
 * + 11/22 for rounding
 */
int
phase_of_the_moon()     /* 0-7, with 0: new, 4: full */
{
    register struct tm *lt = getlt();
    register int epact, diy, goldn;

    diy = lt->tm_yday;
    goldn = (lt->tm_year % 19) + 1;
    epact = (11 * goldn + 18) % 30;
    if ((epact == 25 && goldn > 11) || epact == 24)
        epact++;

    return( (((((diy + epact) * 6) + 11) % 177) / 22) & 7 );
}

这是getlt()函数(也在hacklib.c中):

static struct tm *
getlt()
{
    time_t date;

#if defined(BSD) && !defined(POSIX_TYPES)
    (void) time((long *)(&date));
#else
    (void) time(&date);
#endif
#if (defined(ULTRIX) && !(defined(ULTRIX_PROTO) || defined(NHSTDC))) || (defined(BSD) && !defined(POSIX_TYPES))
    return(localtime((long *)(&date)));
#else
    return(localtime(&date));
#endif
}

这是我的Python代码:

from datetime import date

def phase_of_the_moon():
   lt = date.today()

   diy = (lt - date(lt.year, 1, 1)).days
   goldn = ((lt.year - 1900) % 19) + 1
   epact = (11 * goldn + 18) % 30;
   if ((epact == 25 and goldn > 11) or epact == 24):
      epact += 1
   return ( (((((diy + epact) * 6) + 11) % 177) / 22) & 7 )

import math, decimal, datetime
dec = decimal.Decimal

def position(now=None): 
   if now is None: 
      now = datetime.datetime.now()

   diff = now - datetime.datetime(2001, 1, 1)
   days = dec(diff.days) + (dec(diff.seconds) / dec(86400))
   lunations = dec("0.20439731") + (days * dec("0.03386319269"))

   return lunations % dec(1)

def phase(pos): 
   index = (pos * dec(8)) + dec("0.5")
   index = math.floor(index)
   return {
      0: "New Moon", 
      1: "Waxing Crescent", 
      2: "First Quarter", 
      3: "Waxing Gibbous", 
      4: "Full Moon", 
      5: "Waning Gibbous", 
      6: "Last Quarter", 
      7: "Waning Crescent"
   }[int(index) & 7]

def phase2(pos): 
   return {
      0: "New Moon", 
      1: "Waxing Crescent", 
      2: "First Quarter", 
      3: "Waxing Gibbous", 
      4: "Full Moon", 
      5: "Waning Gibbous", 
      6: "Last Quarter", 
      7: "Waning Crescent"
   }[int(pos)]

def main():
   ## Correct output
   pos = position()
   phasename = phase(pos)
   roundedpos = round(float(pos), 3)
   print "%s (%s)" % (phasename, roundedpos)

   ## My output
   print "%s (%s)" % (phase2(phase_of_the_moon()), phase_of_the_moon())

if __name__=="__main__": 
   main()

Answer 1

编写的代码在很大程度上无法测试-您需要使其可测试。因此，您需要C代码为：

int
phase_of_the_moon()     /* 0-7, with 0: new, 4: full */
{
    register struct tm *lt = getlt();
    return testable_potm(lt);
}

static int
testable_potm(const struct tm *lt)
{
    register int epact, diy, goldn;

    diy = lt->tm_yday;
    goldn = (lt->tm_year % 19) + 1;
    epact = (11 * goldn + 18) % 30;
    if ((epact == 25 && goldn > 11) || epact == 24)
        epact++;

    return( (((((diy + epact) * 6) + 11) % 177) / 22) & 7 );
}

现在，您可以运行具有多个时间值的测试。替代方法是伪造getlt()。

然后，您需要在Python代码中进行并行更改。然后，创建一个time_t可由Python和C读取的值文件，然后将其转换为适当的结构（通过localtime()C语言）。然后，您可以查看发生变化的地方。