计算2个数组的数量差异

use*_*550 1 c# linq

对于A中的每个数字和B中的每个数字(如果它们的差异大于3),请添加新数字

A={6,7,10}
B={2,3}
result={4,5,4,8,7}
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例如 :

6-2 = 4真加4

6-3 = 3假

7-2 = 5真加5

我的尝试:

  var result = A.Select((a, i) => new
  {
   desired = a - B[i] > 3 ? a - B[i] :0

   });
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Adu*_*cci 6

var query = from a in A
            from b in B
            where (a - b) > 3
            select a - b;
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Jon*_*eet 6

这听起来像你想要的:

var query = from a in A
            from b in B
            let diff = a - b
            where diff > 3
            select diff;
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或者用点符号表示,它真的很整齐:

var query = A.SelectMany(a => B, (a, b) => a - b)
             .Where(x => x > 3);
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使用您的测试数据:

using System;
using System.Linq;

class Test
{
    public static void Main()        
    {
        int[] A = {6, 7, 10};
        int[] B = {2, 3};

        var query = A.SelectMany(a => B, (a, b) => a - b)
                     .Where(x => x > 3);

        foreach (var result in query)
        {
            Console.WriteLine(result);
        }
    }
}
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