dismissModalViewControllerAnimated不释放视图控制器

Question

作为我的app启动的一部分,我循环浏览了几个视图控制器.一切正常,但视图控制器未发布.(从不调用viewDidUnload和dealloc).在每次状态更改之前,我会关闭任何呈现的视图控制器.它们被解散,并为每个视图控制器调用viewWillDisappear:

- (void)stateChange:(NSString *)state {

// Dismiss any exiting modals/popups
[self dismissPopup];
[self dismissModalViewControllerAnimated: NO];        

if([state isEqualToString:@"StateBoot"]) {

    CLRemotePrimaryBootViewController * viewControllerBoot = [[CLRemotePrimaryBootViewController alloc]initWithNibName: @"CLRemoteBootView" bundle:nil];
    [self presentModalViewController:viewControllerBoot animated:NO];   
    [viewControllerBoot release];
}

else if([state isEqualToString:@"StateLogin"]) {

    CLRemotePrimaryAuthViewController *viewControllerAuth = [[CLRemotePrimaryAuthViewController alloc]initWithNibName: @"CLRemoteAuthView" bundle:nil];
    [self presentModalViewController:viewControllerAuth animated:NO]; 
    [viewControllerAuth release];
}

else if([state isEqualToString:@"StateMain"]) {

    [self setSelectedIndex:0];
}

else if([state isEqualToString:@"StateStop"]) {

    // TBD
}

}

解雇后,self.presentedViewController实际上是零.关于如何强制iOS发布这些未使用的视图控制器的任何想法？

编辑 -

解决了!希望这篇文章能帮助别人 - 我感到很困惑.事实证明,我的模态视图控制器是从在init方法中设置观察者(NSNotificationCenter)的基类派生的.必须先删除这些观察者,然后才能释放观察视图控制器.在我的情况下,这变得更加困难,因为观察者是块而不是选择器.添加这些观察者时,为每个观察者返回id - 所以我必须在NSMutableArray中跟踪这些并添加一个方法来释放我的基类中的观察者:

+ (void) safeUnsubscribe:(id)object {

if ( object != nil ) {

    if ( [object isKindOfClass:[CLRemotePrimaryBaseViewController class]]) {

        CLRemotePrimaryBaseViewController* viewController = (CLRemotePrimaryBaseViewController*)object;
        [viewController unsubscribe];
    }        
}

}

` - (void)handle:(NSString*)name usingBlock:(CLObjBlock)block {

id observer = [[NSNotificationCenter defaultCenter] addObserverForName:name object:nil queue:nil usingBlock:^(NSNotification * notification){ block([notification object]); }];
[self.observers addObject:observer];    

}`

// Must call before dealloc or listener will never be released!

` - (void)取消订阅{

for ( id observer in self.observers ) {

    [[NSNotificationCenter defaultCenter] removeObserver:observer];
}

[self.observers removeAllObjects];

[[NSNotificationCenter defaultCenter] removeObserver:self];

}

Answer 1

解决了！希望这篇文章对其他人有帮助 - 我很困惑。事实证明，我的模态视图控制器是从在 init 方法中设置观察者（NSNotificationCenter）的基类派生的。在释放观察视图控制器之前，必须删除这些观察者。就我而言，这变得更加困难，因为观察者是块而不是选择器。添加这些观察者时，会返回每个观察者的 id - 因此我必须在 NSMutableArray 中跟踪这些观察者，并添加一个方法来释放我的基类中的观察者：

+ (void) safeUnsubscribe:(id)object {

if ( object != nil ) {
    if ( [object isKindOfClass:[CLRemotePrimaryBaseViewController class]]) {

        CLRemotePrimaryBaseViewController* viewController = (CLRemotePrimaryBaseViewController*)object;
        [viewController unsubscribe];
    }        
}

} 



- (void)handle:(NSString *)name usingBlock:(CLObjBlock)block {

id observer = [[NSNotificationCenter defaultCenter] addObserverForName:name object:nil queue:nil usingBlock:^(NSNotification * notification){ block([notification object]); }];
[self.observers addObject:observer];    

}


// Must call before dealloc or listener will never be released!

- (void)unsubscribe {

for ( id observer in self.observers ) {

    [[NSNotificationCenter defaultCenter] removeObserver:observer];
}

[self.observers removeAllObjects];

[[NSNotificationCenter defaultCenter] removeObserver:self];

}