Man*_*tou 5 mysql sql balance running-total
我有一个包含以下数据的表:
ID In Out
1 100.00 0.00
2 10.00 0.00
3 0.00 70.00
4 5.00 0.00
5 0.00 60.00
6 20.00 0.00
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现在我需要一个查询,它给出了以下结果:
ID In Out Balance
1 100.00 0.00 100.00
2 10.00 0.00 110.00
3 0.00 70.00 40.00
4 5.00 0.00 45.00
5 0.00 60.00 -15.00
6 20.00 0.00 5.00
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是否可以使用一个查询执行此操作,而无需使用触发器或存储过程?
Sim*_*tal 16
简短的回答,是的
更长的答案,你可以使用一个变量来计算它,因为它迭代行,即
SELECT
`table`.`ID`,
`table`.`In`,
`table`.`Out`,
@Balance := @Balance + `table`.`In` - `table`.`Out` AS `Balance`
FROM `table`, (SELECT @Balance := 0) AS variableInit
ORDER BY `table`.`ID` ASC
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在, (SELECT @Balance := 0) AS variableInit你开始之前@Balance被初始化为0保证.然后对于每一行,它将@Balance设置为@Balance + In - Out,然后输出计算的值.
另外值得确定ORDER是否一致,否则Balance会根据返回行的顺序而有所不同.例如,如果您想将其重新排序到前面,则可以将其用作子查询,然后外部查询处理计算值,从而确保平衡保持正确,即
SELECT
`balanceCalculation`.`ID`,
`balanceCalculation`.`In`,
`balanceCalculation`.`Out`,
`balanceCalculation`.`Balance`
FROM (
SELECT
`table`.`ID`,
`table`.`In`,
`table`.`Out`,
@Balance := @Balance + `table`.`In` - `table`.`Out` AS `Balance`
FROM `table`, (SELECT @Balance := 0) AS variableInit
ORDER BY `table`.`ID` ASC
) AS `balanceCalculation`
ORDER BY `balanceCalculation`.`ID` DESC
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