如果IF条件变为真,我如何跳过迭代,并转到do ... end的第一行？

Question

我写了以下代码:

require 'net/http'
require 'uri'
require 'IPAddr'
require 'timeout'
require 'Resolv'
require 'open-uri'

#puts "Origin IP:\n\n"
#originip = gets()
(IPAddr.new("209.85.175.120")..IPAddr.new("209.85.175.150")).each do |address|
  uri = URI("http://#{address.to_s}")
  puts "#{uri}"
  http = Net::HTTP.new(uri.host, uri.port)
  puts "#{http}"
  Net::HTTP.start(uri.host, uri.port) do |http|
    request = Net::HTTP::Get.new uri.request_uri
    response = http.request request
    if response.code == "301" || response.code == "400" then

    end
    #request.initialize_http_header({"Origin" => "#{originip}"})
  end

是否有可能uri = URI("http://#{address.to_s}")在我的if条件下排队

if response.code == "301" || response.code == "400" then
 # condition
end

在上面的代码变成了真的吗？如果条件成立,我怎样才能转到下一个IP地址并跳过当前的IP地址？

是否可以goto在Ruby中执行类似标签和语句的操作？

Answer 1

next if response.code == "301" || response.code == "400"

Answer 2

你想跳到下一个迭代,是吗？只是用next.