如何从R中的列表中删除组件？

Question

我试图从R中的列表中删除一个组件,但它无法正常工作.

我有这样的列表:

> myList
[[1]]
[[1]][[1]]
[1] "Sunny"  "Cloudy" "Rainy" 

[[1]][[2]]
[1] "Warm" "Cold"

[[1]][[3]]
[1] "Normal" "High"  

[[1]][[4]]
[1] "Strong" "Weak"  

[[1]][[5]]
[1] "Warm" "Cool"

[[1]][[6]]
[1] "Same"   "Change"


[[2]]
[[2]][[1]]
[1] "Sunny"  "Cloudy" "Rainy" 

[[2]][[2]]
[1] "Warm" "Cold"

[[2]][[3]]
[1] "Normal" "High"  

[[2]][[4]]
[1] "Strong" "Weak"  

[[2]][[5]]
[1] "Warm" "Cool"

[[2]][[6]]
[1] "Same"   "Change"

我可以删除这样的组件:> myList = mylist[[-particularIndex]]？我想要一个这样的结果:

[[1]]
[[1]][[1]]
[1] "Sunny"  "Cloudy" "Rainy" 

[[1]][[2]]
[1] "Warm" "Cold"

[[1]][[3]]
[1] "Normal" "High"  

[[1]][[4]]
[1] "Strong" "Weak"  

[[1]][[5]]
[1] "Warm" "Cool"

[[1]][[6]]
[1] "Same"   "Change"

我无法为该列表创建字符串名称标签.我必须引用行index(particular index)(使用rownames(myList)删除的东西不会帮助我).

Answer 1

我认为你非常接近正确答案:

> x <- list(list(1:3, 4:6), list(4:7, 2:3), list(4:6,1:2))
> x[-2]
[[1]]
[[1]][[1]]
[1] 1 2 3

[[1]][[2]]
[1] 4 5 6


[[2]]
[[2]][[1]]
[1] 4 5 6

[[2]][[2]]
[1] 1 2

以上工作摆脱了原来的第二个组件.注意单方括号,并与:

X [[ - 2]]

Error in x[[-2]] : attempt to select more than one element

双重支架不起作用.(实际上,如果列表中只有两个组件,那么它确实有效,但不依赖于它.)

有很多地方可以解释单方括号和双方括号.其中之一是'The R Inferno'的Circle 8.1.54 http://www.burns-stat.com/pages/Tutor/R_inferno.pdf