我需要读取从Web服务返回的XML文件.
我正在学习本教程,我在这行中有错误:
Element firstPersonElement = (Element)firstPersonNode;
错误:
inconvertible types
required: javax.swing.text.html.parser.Element
found: org.w3c.dom.Node
我究竟做错了什么?
提前致谢.
编辑
我的进口
import br.com.portaldeideias.model.ErroXML;
import br.com.portaldeideias.model.TributosNFe;
import java.io.StringReader;
import java.util.List;
import javax.jws.WebMethod;
import javax.jws.WebParam;
import javax.jws.WebService;
import javax.swing.text.html.parser.Element;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.transform.Source;
import javax.xml.transform.dom.DOMSource;
import org.w3c.dom.Document;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.InputSource;
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你的进口错了.确保导入正确.
去掉 import javax.swing.text.html.parser.Element
确保导入是:
import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
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作为额外检查,确保节点是元素节点类型.
if (firstPersonNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) firstPersonNode;
...................
}
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