使用多值键创建RouteValueDictionary

Dav*_*eer 14 asp.net-mvc routes asp.net-mvc-3

我想返回一个RedirectToRouteResult将用户发送到以下URL的URL:

/MyController/MyAction/id?newid=3&newid=5&newid=7
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newid参数有几个值.

我的电话看起来像: return RedirectToAction(string.Empty, routeValues);

这是我到目前为止所尝试的,但是不起作用:

// ...?newid%5B0%5D=3&newid%5B1%5D=5&newid%5B2%5D=7
var routeValues = new RouteValueDictionary {
    {"id", myid},
    {"newid[0]", 3},
    {"newid[1]", 5},
    {"newid[2]", 7},
};

// ...?newid=System.Int32%5B%5D
var routeValues = new { id = myid, newid = new int[] { 3, 5, 7 } };

// ...?newid=System.String%5B%5D
var routeValues = new { id = myid, newid = new string[] { "3", "5", "7" } };

// ...?newid=System.Int32%5B%5D
var routeValues = new RouteValueDictionary {
    {"id", myid},
    {"newid", new int[] { 3, 5, 7 } }
};
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使这项工作的秘诀是什么?

Dar*_*rov 13

这是框架中真正缺少的一件事.你最好的选择是手动滚动它:

public ActionResult Foo()
{
    var ids = new[] { 3, 5, 7 };
    var url = new UriBuilder(Url.Action("MyAction", "MyController", new { id = "123" }, Request.Url.Scheme));
    url.Query = string.Join("&", ids.Select(x => "newid=" + HttpUtility.UrlEncode(x.ToString())));
    return Redirect(url.ToString());
}
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将其置于自定义扩展方法中可以提高当然的可读性.