如何通过servlet中的ajax获取数据？

Question

我想将页面上的一些数据发送到servlet

所以我写了下面的jquery来做这件事

我使用所有数据来构建一个json字符串,并直接将其发送到servlet

但我不知道如何从servlet中的ajax获取整个数据

$("#save").click
(
    function()
    {
        $.ajax
        (
            {
                url:'/WebApplication1/Controller',
                data:'{"name":"abc","address":"cde"}',
                type:'post',
                cache:false,
                success:function(data){alert(data);},
                error:function(){alert('error');}
            }
        );
    }
);

如果从chrome看到请求标头的Form Data段

你会看到整个json字符串是关键.

Request URL:http://192.168.0.13/WebApplication1/Controller
Request Method:POST
Status Code:404 Not Found
Request Headersview source
Accept:*/*
Accept-Charset:Big5,utf-8;q=0.7,*;q=0.3
Accept-Encoding:gzip,deflate,sdch
Accept-Language:zh-TW,zh;q=0.8,en-US;q=0.6,en;q=0.4
Connection:keep-alive
Content-Length:112
Content-Type:application/x-www-form-urlencoded
Host:192.168.0.13
Origin:http://192.168.0.13
Referer:http://192.168.0.13/system_admin/building.html
User-Agent:Mozilla/5.0 (Windows NT 6.1; WOW64) AppleWebKit/535.7 (KHTML, like Gecko) Chrome/16.0.910.0 Safari/535.7
X-Requested-With:XMLHttpRequest
Form Dataview URL encoded
{"name":"abc","address":"cde"}:
Response Headersview source
Accept-Ranges:bytes
Connection:Keep-Alive
Content-Language:en
Content-Type:text/html; charset=iso-8859-1
Date:Wed, 15 Feb 2012 12:37:24 GMT
Keep-Alive:timeout=5, max=100
Server:Apache/2.2.14 (Win32) DAV/2 mod_ssl/2.2.14 OpenSSL/0.9.8l mod_autoindex_color PHP/5.3.1
Transfer-Encoding:chunked
Vary:accept-language,accept-charset

Answer 1

看这里,

data:'{"name":"abc","address":"cde"}',

你的data归因是错误的.它不应该是字符串,而是真正的JSON对象.删除那些单引号.

data:{"name":"abc","address":"cde"},

通过这种方式,它可以在servlet中以通常的方式使用

String name = request.getParameter("name"); // abc
String address = request.getParameter("address"); // cde

也可以看看:

• jQuery.ajax() 文件