SQL Server - 将 TIME 值舍入到下一分钟

Question

我发现了很多关于四舍五入“向下”时间值的帖子（例如/sf/answers/466692901/），但我有另一个问题：我想四舍五入到更高的分钟而不是更低的分钟，如何我可不可以做？

我的代码：

SELECT

 PA.ORE AS TOT_HOURS,  
 CAST(CAST(PA.ORA_INIZIO AS DATETIME) AS TIME) AS BEGIN_TIME,
 CAST(dateadd(minute, datediff(minute, 0, (CAST(PA.ORA_INIZIO AS DATETIME))), 0) AS TIME) AS BEGIN_TIME_ROUNDED


FROM PRG_ATTIVITA PA INNER JOIN PRG_TIPI_ATTIVITA PTA ON  PA.ID_TIPO_ATTIVITA = PTA.ID_TIPO_ATTIVITA
                     INNER JOIN PER_ANAGRAFICA PAN ON PA.ID_DIPENDENTE = PAN.ID_DIPENDENTE
WHERE PA.ID_PROGETTO = 1431 and pta.DESCR_TIPO_ATTIVITA like 'F-%remoto%' and ID_ATTIVITA = 41772 

ORDER BY  PA.DATA_ATTIVITA

我的结果如下：

    TOT_HOURS   BEGIN_TIME          BEGIN_TIME_ROUNDED
    1.50        15:59:59.9970000    15:59:00.0000000

我想要 BEGIN_TIME_ROUNDED = 16:00:00.0000000

注意： 1. 我必须转换我的数据 { CAST(PA.ORA_INIZIO AS DATETIME) } 因为在数据库中我有时间数据作为浮点值 2. BEGIN_TIME 是转换后我的时间值的实际值

Answer 1

SELECT  DATEADD(MINUTE, CEILING(DATEDIFF(SECOND, 0, CAST(CAST(PA.ORA_INIZIO AS DATETIME) AS TIME)) / 60.0), DATEDIFF(DAY, 0, PA.ORA_INIZIO)) AS BEGIN_TIME_ROUNDED

编辑

正如评论中指出的，此操作会在 0 到 1 秒之间失败。只需将上限精度从秒更改为毫秒即可解决此问题：

SELECT  PA.ORA_INIZIO,
        DATEADD(MINUTE, 
            CEILING(DATEDIFF(MILLISECOND, 0, CAST(PA.ORA_INIZIO AS TIME)) / 60000.0),
            DATEDIFF(DAY, 0, PA.ORA_INIZIO)) AS BEGIN_TIME_ROUNDED
FROM (VALUES 
        (CONVERT(DATETIME, '20211126 15:59:00.997')), 
        (CONVERT(DATETIME, '20211126 15:59:00.004'))
    ) AS PA (ORA_INIZIO);

这使：

ORA_INIZIO	BEGIN_TIME_ROUNDED
2021-11-26 15:59:59.997	2021-11-26 16:00:00.000
2021-11-26 15:59:00.003	2021-11-26 16:00:00.000