G ++编译器错误 - 此处首先需要合成方法

Question

这是错误:

In file included from /usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/ios:39,
                 from /usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/ostream:40,
                 from /usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/iostream:40,
                 from date.h:15,
                 from date.cpp:13:
/usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/bits/ios_base.h: In copy constructor ‘std::basic_ios<char, std::char_traits<char> >::basic_ios(const std::basic_ios<char, std::char_traits<char> >&)’:
/usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/bits/ios_base.h:790: error: ‘std::ios_base::ios_base(const std::ios_base&)’ is private
/usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/iosfwd:47: error: within this context
/usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/iosfwd: In copy constructor ‘std::basic_ostream<char, std::char_traits<char> >::basic_ostream(const std::basic_ostream<char, std::char_traits<char> >&)’:
/usr/lib/gcc/x86_64-redhat-linux/4.4.6/../../../../include/c++/4.4.6/iosfwd:56: note: synthesized method ‘std::basic_ios<char, std::char_traits<char> >::basic_ios(const std::basic_ios<char, std::char_traits<char> >&)’ first required here 
date.cpp: In function ‘std::ostream operator<<(std::ostream&, Date&)’:
date.cpp:389: note: synthesized method ‘std::basic_ostream<char, std::char_traits<char> >::basic_ostream(const std::basic_ostream<char, std::char_traits<char> >&)’ first required here 
make: *** [date.o] Error 1

我认为它可能与我的头文件和源文件如何编译在一起所以这里是代码:

标题:

#ifndef DATE_H
#define DATE_H

#include <iostream>
using namespace std;

// basic but lengthy class code

#endif

资源:

// #include <iostream>  // tried compiling with and without this, but no change
#include <cassert>
#include <cstdlib>
#include "date.h"       // this is (date.cpp:13)
// I have tried using namespace std, just to see what would happen but nothing changed

最后,这是编译器引用的函数(date.cpp:389):

ostream operator <<(ostream &out, const Date &date)
{
    // day                                                                      
    out << date.day;
    switch (date.day)
    {
        case 1:
        case 21:
        case 31:
            out << "st";
            break;
        case 2:
        case 22:
            out << "nd";
            break;
        case 3:
        case 23:
            out << "rd";
            break;
        default:
            out << "th";
            break;
    }

    // month                                                                    
    const char MONTHS[12][10] =
    { "January", "February", "March",     "April",   "May",      "June",
        "July",    "August",   "September", "October", "November", "December"};

    out << " of " << MONTHS[date.month - 1] << ", ";

    // year                                                                     
    out << date.year;

    return out;
}

我在这里完全不知所措.我在谷歌搜索了最后一小时,但我找不到任何解决我问题的方法.在此先感谢您的帮助!

Answer 1

问题是你无法回归平原ostream.您必须返回对您收到的参考作为参数的引用(注意&).

ostream & operator <<(ostream &out, const Date &date)

编译器抱怨它无法ostream通过复制out行来创建新对象return out;.