使用sed/grep/awk删除所有内容,直到第一个空白行

Question

任何人都可以帮我弄清楚如何做到这一点,我将不胜感激.

例

block of            //delete
non-important text  //delete

important text      //keep
more important text //keep

Answer 1

sed '1,/^$/d' file

要么

awk '!$0{f=1;next}f{print}' file

产量

$ sed '1,/^$/d' <<< $'block of\nnon-important text\n\nimportant text\nmore important text'
important text
more important text

$ awk '!$0{f=1;next}f{print}' <<< $'block of\nnon-important text\n\nimportant text\nmore important text'
important text
more important text

Answer 2

如果空白行为空,则执行此操作:

sed '1,/^$/d' filename