如何将hibernate查询结果作为列表或hashmap的关联数组获取

Question

我正在开发struts 2和hibernate 3中的应用程序.

我有3张桌子

1. 检查
2. InspectionMission
3. 时间线

Inspection与...相关联InspectionMission并InspectionMission与之相关联Timeline.

现在我有以下问题.我在HQL中编写了以下查询

public List getQuartewiseInspectionList(){

   Session session = HibernateUtil.getSessionFactory().getCurrentSession();

   Query q = session.createQuery(
                "select count(i.inspectionId) as tot_inspections,t.year,t.quarter" +
                " From Inspection as i " +
                " inner join i.inspectionMission as im inner join im.timeline as t" +
                " GROUP by t.year,t.quarter");

   return q.list();

}

我想获取结果如下

result[0][tot_inspections] = "6"
result[0][year] = "2009";
result[0][quarter] = "Q2";

result[1][tot_inspections] = "3"
result[1][year] = "2009";
result[1][quarter] = "Q3";

等等,以便我可以在jsp struts中显示它,如下所示:

在JSP中,我编写了以下代码

<table border="1">

   <s:iterator value="result" status="status">
       <tr class="<s:if test="#status.even">even</s:if><s:else>odd</s:else>">
             <td class="nowrap"><s:property value="tot_inspections" /></td>
             <td class="nowrap"><s:property value="year" /></td>
             <td class="nowrap"><s:property value="quarter" /></td>
       </tr>         
    </s:iterator>
</table>

这里有人能帮帮我吗？

Answer 1

你必须使用"新地图"语法(Hibernate Reference第14.6段)

select new map(count(i.inspectionId) as tot_inspections, t.year as year, t.quarter as quarter) from ...

查询的其余部分是相同的.这将返回一个映射列表,其中键是"列"的别名.