我怎样才能将数组分配给php中的另一个变量?

pro*_*mer -1 php arrays variable-assignment

我在php中定义了一个数组

    $letters = array("A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","W","V","X","Y","Z");
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然后我尝试将数组分配给一个将成为数组的新变量,我这样做:

   $new_array = array();
   $new_array =  $letters;
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但它不起作用,为什么?

cra*_*231 8

你可以这样做

$new_array = $letters;
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您不必指定类型,因为它是隐含的.

  • 现在,我很困惑..这不是他的意思吗?为什么声明`$ new_array`的类型会改变什么?有人,请解释一下.[它在这里工作](http://ideone.com/YlP86) (3认同)