Vol*_*ike 15 mysql sql group-by isnull notnull
我有一个简单的安装表:
如果install_slot为NULL,则它是可用的安装槽.不为null - 然后,使用插槽.我需要返回给定产品和电子邮件的总安装结果,以及给定产品和电子邮件的已安装结果.我想我可以用两个查询来做这个,但是想知道是否有一种SQL方法可以在一个中完成所有操作?
我尝试了以下作为一个疯狂的猜测,但它没有奏效.
SELECT
i1.`prod_code`,
COUNT(i1.`email`) AS total_installs,
COUNT(ISNULL(i2.`install_slot`)) AS used_installs
FROM
`installs` AS i1
JOIN
`installs` AS i2
ON
i1.`prod_code` = i2.`prod_code`
WHERE
i1.`email` = 'example@example.com'
GROUP BY
i1.`prod_code`,i2.`prod_code`
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dgw*_*dgw 36
SELECT prod_code,
COUNT(email) AS total_installs,
COUNT(install_slot) AS used_installs
FROM installs
WHERE email='example@example.com'
GROUP BY prod_code
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COUNTNOT NULL仅计算值.
小智 6
提供的解决方案对我不起作用.我不得不修改如下:
SELECT prod_code,
COUNT(NULLIF(email,'')) AS total_installs,
COUNT(NULLIF(install_slot,'')) AS used_installs
FROM installs
WHERE email='example@example.com'
GROUP BY prod_code
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