PHP/JSON解析

Question

Array
(
    [0] => Array
    (
        [faq_id] => 14
        [faq_faqcat_id] => 3
        [faq_order] => 8
        [faq_subject] => 800018
        [faq_content] => 800019
        [faq_datecreated] => 1213382678
        [faq_dateupdated] => 1215547984
        [faq_views] => 22
    )

    [1] => Array
    (
        [faq_id] => 15
        [faq_faqcat_id] => 3
        [faq_order] => 9
        [faq_subject] => 800020
        [faq_content] => 800021
        [faq_datecreated] => 1213382698
        [faq_dateupdated] => 1215547986
        [faq_views] => 13
    )

    [2] => Array
    (
        [faq_id] => 16
        [faq_faqcat_id] => 3
        [faq_order] => 10
        [faq_subject] => 800022
        [faq_content] => 800023
        [faq_datecreated] => 1213382711
        [faq_dateupdated] => 1215547988
        [faq_views] => 15
    )
)

以上数据是PHP脚本的输出.我必须将其转换为JSON对象并在iPhone上显示.谁能告诉你怎么样？

Answer 1

看一下json_encode和json_decode函数

对于iOS上的解析部分,您可以使用本机NSJSONSerialization类.