检查PHP多维数组中是否存在数组值

Question

我有以下多维数组:

Array ( [0] => Array 
         ( [id] => 1 
           [name] => Jonah 
           [points] => 27 )
        [1] => Array 
         ( [id] => 2 
           [name] => Mark 
           [points] => 34 )
      )

我正在使用foreach循环从数组中提取值:

foreach ($result as $key => $sub)
{
    ...
}

但我想知道如何查看数组中的值是否已存在.

所以例如,如果我想向数组中添加另一个集合,但是id是1(所以这个人是Jonah)并且他们的分数是5,我可以将5添加到已创建的数组值id 0而不是创建新的数组值？

所以在循环完成后,数组将如下所示:

Array ( [0] => Array 
         ( [id] => 1 
           [name] => Jonah 
           [points] => 32 )
        [1] => Array 
         ( [id] => 2 
           [name] => Mark 
           [points] => 34 )
      )

Answer 1

怎么样循环你的数组,检查每个项目是否id是你正在寻找的项目？

$found = false;
foreach ($your_array as $key => $data) {
    if ($data['id'] == $the_id_youre_lloking_for) {
        // The item has been found => add the new points to the existing ones
        $data['points'] += $the_number_of_points;
        $found = true;
        break; // no need to loop anymore, as we have found the item => exit the loop
    }
}

if ($found === false) {
    // The id you were looking for has not been found, 
    // which means the corresponding item is not already present in your array
    // => Add a new item to the array
}