Rob*_*_UK 8 mysql group-by count
select count(*) as count from table
group by foreign_id order by count
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这将返回每个外部ID的多个匹配项.然而,我正在寻找的是总结结果.
结果将是:
10 results grouping 1 elements
5 results grouping 2 elements
7 results grouping 7 elements
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Mos*_*cho 13
好的,我知道了.问题的标题比问题本身更好地表达了它:)
您需要先了解每个FK出现的次数:
select count(*) as GroupAmount from t1
group by foreign_id
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一旦你有了这个,你必须将它们分组,以获得每个项目出现的次数与上面相同.这将导致:
select GroupAmount, count(*) GroupAmountTimes from (
select count(foreign_id) as GroupAmount from t1
group by foreign_id
) as SubQuery
group by GroupAmount
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在这里看到它
小智 5
计算组返回的组数:
select foreign_id as GroupAmount, count(foreign_id) as GroupAmountTimes
from t1
group by foreign_id
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http://sqlfiddle.com/#!2/35661/42
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