jps*_*yes 7 php api salesforce
我是使用salesforce api的新手.我已经下载了saleforce/php工具包,并且能够从我服务器上的webform成功创建联系人和帐户.
要创建联系人,我正在执行以下操作:
$records[0] = new stdclass();
$records[0]->FirstName = $FirstName;
$records[0]->LastName = $LastName;
$records[0]->Email = $Email;
$records[0]->Phone = $Phone;
$records[0]->MailingStreet = $MailingStreet;
$records[0]->MailingCity = $MailingCity;
$records[0]->MailingState = $MailingState;
$records[0]->MailingPostalCode = $MailingPostalCode;
$records[0]->MailingCountry = $MailingCountry;
$records[0]->LeadSource = $LeadSource;
$create = $mySforceConnection->create($records, 'Contact');
Run Code Online (Sandbox Code Playgroud)
要创建帐户,我正在执行以下操作
$records[0] = new stdclass();
$records[0]->Name = $Name
$create = $mySforceConnection->create($records, 'Account');
Run Code Online (Sandbox Code Playgroud)
任何人都可以给我一个简单的例子,说明如何将联系人与帐户相关联?
我在表单上有一个复选框,询问这是否是一个组织.如果用户选中此框,我想创建一个包含某些数据的组织帐户,并创建与某些数据的联系并将两者相关联.
我并不是在寻找一个完整的工作实例,而是更多的只是让我指向正确的方向.
假设我有一个ID为001Z0000004XeWfIAK的帐户
我试过了
$records[0] = new stdclass();
$records[0]->FirstName = $FirstName;
$records[0]->LastName = $LastName;
$records[0]->Email = $Email;
$records[0]->Phone = $Phone;
$records[0]->MailingStreet = $MailingStreet;
$records[0]->MailingCity = $MailingCity;
$records[0]->MailingState = $MailingState;
$records[0]->MailingPostalCode = $MailingPostalCode;
$records[0]->MailingCountry = $MailingCountry;
$records[0]->LeadSource = $LeadSource;
$records[0]->AccountId = '001Z0000004XeWfIAK';
$create = $mySforceConnection->create($records, 'Contact');
Run Code Online (Sandbox Code Playgroud)
@ superfell
它返回:
Array
(
[0] => stdClass Object
(
[errors] => Array
(
[0] => stdClass Object
(
[message] => A Household Contact's account must be a household.
[statusCode] => FIELD_CUSTOM_VALIDATION_EXCEPTION
)
)
[id] =>
[success] =>
)
)
但我试图将联系人与orginization联系起来
联系方式有一个AccountId领域.因此,下面的代码假定您在名为的变量中拥有帐户ID,$accountId并且$resource[0]是您要关联的联系人.
$records[0]->AccountId = $accountId
$mySforceConnection->update($records)
Run Code Online (Sandbox Code Playgroud)
我不太了解php,但我认为这将接近正确.
好的,我自己也在回答这个问题,因为我不能将Superfell的评论标记为答案.但他的评论
"当您创建帐户时,您需要将recordTypeId设置为不是家庭记录类型的记录类型. - superfell"
帮助我得到了答案.
这是我创建帐户的最终代码,然后是该帐户的联系人.
//First I create a simple account
//With no recordTypeId specified it defaults to the the type I want
$records[0] = new stdclass();
$records[0]->Name = $Name;
//Create a new orginization account
$org = $mySforceConnection->create($records, 'Account');
Run Code Online (Sandbox Code Playgroud)
创建帐户后,Salesforce将使用新的AccountId返回成功消息
Array
(
[0] => stdClass Object
(
[id] => 001Z0000004XfXcIAK
[success] => 1
)
)
然后,我可以创建一个联系人并将其与我的新帐户关联
$contact[0] = new stdclass();
$contact[0]->FirstName = $FirstName;
$contact[0]->LastName = $LastName;
$contact[0]->Email = $Email;
$contact[0]->Phone = $Phone;
$contact[0]->MailingStreet = $MailingStreet;
$contact[0]->MailingCity = $MailingCity;
$contact[0]->MailingState = $MailingState;
$contact[0]->MailingPostalCode = $MailingPostalCode;
$contact[0]->MailingCountry = $MailingCountry;
$contact[0]->LeadSource = $LeadSource;
//This is where my problem was, Thanks again superfell
//$organization_contact = My custom Salesforce contact type ID, E.G. recordTypeId
$contact[0]->recordTypeId = $orginization_contact;
//The AccountId is the account I want to associate this contact with.
//AccountId was returned by Salesforce upon the creation of the account (See above)
$contact[0]->AccountId = $org[0]->id;
$contact = $mySforceConnection->create($contact, 'Contact');
Run Code Online (Sandbox Code Playgroud)
再次感谢Jeremey和Superfell.节省了我几个小时.
| 归档时间: |
|
| 查看次数: |
4785 次 |
| 最近记录: |