eek*_*142 3 sql-server join distinct

我的原始数据在表2中.我从头开始创建Table1.我填充了A列,如下所示:
INSERT INTO Table1("item")
SELECT DISTINCT(Table2."item")
FROM Table2
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我填充了Table1.Totals(B列),如下所示:
UPDATE Table1
SET totals = t2.q
FROM Table1 INNER JOIN
(
SELECT t2."item"
, SUM(t2.quantity) AS q
FROM t2
GROUP BY t2."item"
) AS t2
ON Table1."item" = t2."item"
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如何填充Table1."date"?我上面的UPDATE在这里不起作用,因为我不能在日期上使用聚合函数.我能够在单独的查询中使用以下代码获得我想要的结果:
SELECT DISTINCT Table1."item"
, Table2."date"
FROM Table1 INNER JOIN Table2
ON Table1."item" = Table2."item"
ORDER BY Table1."item"
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但是,如何使用此查询的结果来设置列的值?我正在使用SQL Server 2008.
如果你不能像@Lamak建议的那样重新插入,那么你可以UPDATE这样做:
UPDATE t1
SET t1.Date = s.Date
FROM Table1 AS t1
INNER JOIN
(
SELECT Item, [Date] = MAX([Date]) -- or MIN()
FROM Table2
GROUP BY Item
) AS s
ON t1.Item = s.Item;
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