如何进行批量搜索并用Perl替换？

Question

我有以下脚本,它接收输入文件,输出文件并用其他字符串替换输入文件中的字符串并写出输出文件.

我想更改脚本遍历文件目录,即不是提示输入和输出文件,脚本应该将目录路径作为参数,例如C:\ temp\allFilesTobeReplaced \并搜索字符串x并替换它使用y表示该目录路径下的所有文件并写出相同的文件.

我该怎么做呢？

谢谢.

$file=$ARGV[0];

open(INFO,$file);
@lines=<INFO>;
print @lines;

open(INFO,">c:/filelist.txt");

foreach $file (@lines){
   #print "$file\n";
   print INFO "$file";
}

#print "Input file name: ";
#chomp($infilename = <STDIN>);

if ($ARGV[0]){
   $file= $ARGV[0]
}

print "Output file name: ";
chomp($outfilename = <STDIN>);
print "Search string: ";
chomp($search = <STDIN>);
print "Replacement string: ";
chomp($replace = <STDIN>);

open(INFO,$file);
@lines=<INFO>;
open(OUT,">$outfilename") || die "cannot create $outfilename: $!";

foreach $file (@lines){    
    # read a line from file IN into $_
    s/$search/$replace/g; # change the lines
    print OUT $_; # print that line to file OUT
}
close(IN);
close(OUT);

Answer 1

使用perl单衬垫

perl -pi -e 's/original string/new string/' filename

可以结合使用File::Find,给出以下单个脚本(这是我用于许多此类操作的模板).

use File::Find;

# search for files down a directory hierarchy ('.' taken for this example)
find(\&wanted, ".");

sub wanted
{
    if (-f $_)
    {
        # for the files we are interested in call edit_file().
        edit_file($_);
    }
}

sub edit_file
{
    my ($filename) = @_;

    # you can re-create the one-liner above by localizing @ARGV as the list of
    # files the <> will process, and localizing $^I as the name of the backup file.
    local (@ARGV) = ($filename);
    local($^I) = '.bak';

    while (<>)
    {
        s/original string/new string/g;
    }
    continue
    {
        print;
    }
}