Mt *_* Kr 4 sql t-sql sql-server sql-server-2005
我有三个表orders,orders_delivered,orders_delivered_sta,三个表中的数据如下
餐桌订单
orders_id
10
11
12
13
Run Code Online (Sandbox Code Playgroud)
表orders_delivered
orders_delivered_id orders_id
10 1000
10 1001
11 1002
12 1003
12 1004
13 1005
13 1006
13 1007
Run Code Online (Sandbox Code Playgroud)
表orders_delivered_sta
orders_delivered_sta_id orders_delivered_id date now_ind
1 1000 02/11/2011 0
2 1000 01/10/2006 0
3 1000 09/13/2011 0
4 1001 01/19/2010 0
5 1001 02/21/2011 0
6 1002 02/11/2009 0
7 1002 08/27/2010 0
8 1003 07/15/2012 0
9 1004 03/09/2007 0
10 1010 10/01/2010 0
11 1011 03/27/2011 0
12 1012 07/25/2010 0
13 1013 09/18/2004 0
Run Code Online (Sandbox Code Playgroud)
所以我需要更新orders_delivered_sta表,这样对于一个orders_delivered_id的最大日期,now_ind应该为1,就像一个orders_delivered_id 1000一样,对于这组orders_delivered_id和日期(1000,09/13/2011),最大日期是2011年9月13日now_ind 应为 1,如果 orders_delivered_id 列有且只有一个 id,则应将其更改为 1
order_delivered_sta 表中有一些数据不在orders 中,而orders_delivered 表中则不需要更改。oreders_delivered 表中的orders_delivered_id 只需要更改
所以所需的输出应该是这样的
表orders_delivered_sta
orders_delivered_sta_id orders_delivered_id date now_ind
1 1000 02/11/2011 0
2 1000 01/10/2006 0
3 1000 09/13/2011 1
4 1001 01/19/2010 0
5 1001 02/21/2011 1
6 1002 02/11/2009 0
7 1002 08/27/2010 1
8 1003 07/15/2012 1
9 1004 03/09/2007 1
10 1010 10/01/2010 0
11 1011 03/27/2011 0
12 1012 07/25/2010 0
13 1013 09/18/2004 0
Run Code Online (Sandbox Code Playgroud)
表结构:
create table orders
(
order_id int primary key
)
insert into orders select 10
insert into orders select 11
insert into orders select 12
insert into orders select 13
create table orders_delivered
(
orders_delivered_id int primary key,
orders_id int FOREIGN KEY(orders_id)REFERENCES orders (orders_id)
)
insert into orders_delivered select 1000,10
insert into orders_delivered select 1001,10
insert into orders_delivered select 1002,11
insert into orders_delivered select 1003,12
insert into orders_delivered select 1004,12
insert into orders_delivered select 1005,13
insert into orders_delivered select 1006,13
insert into orders_delivered select 1007,13
create table orders_delivered_sta
(
orders_delivered_sta_id int primary key,
orders_delivered_id int FOREIGN KEY(orders_delivered_id)REFERENCES orders_delivered (orders_delivered_id),
date char(10),
now_ind int
)
insert into orders_delivered_sta select 1,1000,'02/11/2011', 0
insert into orders_delivered_sta select 2,1000,'01/10/2006', 0
insert into orders_delivered_sta select 3,1000,'09/13/2011', 0
insert into orders_delivered_sta select 4,1001,'01/19/2010', 0
insert into orders_delivered_sta select 5,1001,'02/21/2011', 0
insert into orders_delivered_sta select 6,1002,'02/11/2009', 0
insert into orders_delivered_sta select 7,1002,'08/27/2010', 0
insert into orders_delivered_sta select 8,1003,'07/15/2012', 0
insert into orders_delivered_sta select 9,1004,'03/09/2007', 0
insert into orders_delivered_sta select 10,1010,'10/01/2010', 0
insert into orders_delivered_sta select 11,1011,'03/27/2011', 0
insert into orders_delivered_sta select 12,1012,'07/25/2010', 0
insert into orders_delivered_sta select 13,1013,'09/18/2004', 0
Run Code Online (Sandbox Code Playgroud)
您可以使用 CTE 和窗口MAX():
;
WITH max_dates AS (
SELECT
*,
max_date = MAX(date) OVER (PARTITION BY orders_delivered_id)
FROM orders_delivered_sta
WHERE orders_delivered_id IN (SELECT orders_delivered_id FROM orders_delivered)
)
UPDATE max_dates
SET now_ind = 1
WHERE date = max_date
Run Code Online (Sandbox Code Playgroud)
参考:
| 归档时间: |
|
| 查看次数: |
9555 次 |
| 最近记录: |