订阅中的SSRS默认参数值

Question

订阅中的SSRS默认参数值

Gab*_*abe 2 reporting-services ssrs-2008

我有一个报告,其中包含用户输入的两个必需日期参数.我想创建一个在周五运行的订阅,该订阅将在前一周的周日到周六期间进行.因此,例如,对于即将到来的星期五,订阅将在1月29日 - 2月4日进行.我已经尝试过=Now(), =Today(), @ExecutionTime然后减去天数,但我得到的只是错误.这可能吗？

我确实看到了这个链接,但我想知道是否有更好的方法. http://www.sqlservercentral.com/articles/Development/datadrivensubscriptions/2432/

SSRS 2008

Answer 1

Jon*_*onH 6

是的我已经这样做了,请看这篇文章/sf/answers/387773081/ 您可以创建一个获取日期范围并在报告中使用它的数据集.然后,您的订阅可以使用此日期范围并动态更改,而无需每天/每周/每月/每年/等手动更改.

转发此处,这是您最灵活的解决方案:

我还将分享一组我使用的常用日期函数.只需将其创建为表值函数:

set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
go

CREATE FUNCTION [dbo].[udfCommonDates] (@date datetime)
RETURNS @t table (week_start datetime,
                  week_end datetime,
                  lastweek_start datetime,
                  lastweek_end datetime,
                  month_start datetime,
                  month_end datetime,
                  lastmonth_start datetime,
                  lastmonth_end datetime,
                  yesterday_start datetime,
                  yesterday_end datetime,
                  today_start datetime,
                  today_end datetime,
                  thisweek_monday_start datetime,
                  thisweek_monday_end datetime,
                  year_start datetime,
                  year_end datetime,
                  tomorrow_noon datetime,
                  today_noon datetime,
                  date_only datetime)
BEGIN
   INSERT @t
   SELECT
   dbo.get_week_start ( @date ) AS week_start,
   dbo.get_week_end   ( @date ) AS week_end,
   dbo.get_week_start ( DATEADD(d, -7, @date ) ) AS lastweek_start,
   dbo.get_week_end   ( DATEADD(d, -7, @date ) ) AS lastweek_end,
   dbo.get_month_start( @date ) AS month_start,
   dbo.get_month_end  ( @date ) AS month_end,
   dbo.get_month_start ( DATEADD(m,-1, @date) ) AS lastmonth_start,
   dbo.get_month_end  ( DATEADD(m,-1,@date) ) AS lastmonth_end,
   dbo.get_yesterday_start ( @date ) AS yesterday_start,
   dbo.get_yesterday_end ( @date ) AS yesterday_end,
   dbo.get_today_start (@date) AS today_start,
   dbo.get_today_end ( @date ) AS today_end,
   dbo.get_weekday_start(1,@date) AS thisweek_monday_start,
   dbo.get_weekday_end(1,@date) AS thisweek_monday_end,
   dbo.get_year_start(@date) AS year_start,
   dbo.get_year_end(@date) AS year_end,  
   dbo.get_tomorrow_noon(@date) AS TomorrowNoon,
   dbo.get_today_noon(@date) AS TodayNoon,
   dbo.get_date_only(@date) AS DateOnly
RETURN
END

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以下是这些标量值函数:

    CREATE FUNCTION [dbo].[get_date_only] (@date datetime)
    RETURNS datetime
    WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
    AS    
    BEGIN
        RETURN dateadd(day, DateDiff(day, 0, GetDate()), 0)
    END
    GO

CREATE FUNCTION [dbo].[get_month_end] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    
BEGIN
   RETURN dateadd(ms, -3, dateadd (m,datediff(m,0,
          dateadd(m,1,@date)),0))
END
GO

CREATE FUNCTION [dbo].[get_month_start] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    
BEGIN
   RETURN dateadd(m,datediff(m,0, @date),0)
   END
GO

CREATE FUNCTION [dbo].[get_today_end] (@today datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    
BEGIN
   return dateadd(ms, -3, datediff(d,0,dateadd(d,1,@today)))
END
GO

CREATE FUNCTION [dbo].[get_today_noon](@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   RETURN DATEADD(hh, 12, DATEADD(d,DATEDIFF(d,0, @date),0))
END
GO

CREATE FUNCTION [dbo].[get_today_start] (@today datetime)
RETURNS datetime 
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(day, 0, datediff(d,0,@today))
END
GO

CREATE FUNCTION [dbo].[get_tomorrow_noon](@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   RETURN DATEADD(hh, 12, DATEADD(d,DATEDIFF(d,-1, @date),0))
END
GO

CREATE FUNCTION [dbo].[get_week_end] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(yyyy, datepart(yyyy,
      dateadd(weekday,7-datepart(weekday, @date),@date))-1900, 0)
    + dateadd(ms, -3,
      dateadd(dy, datepart(dy,
     dateadd(weekday,7-datepart(weekday, @date),@date)),0) )
END
GO

CREATE FUNCTION [dbo].[get_week_start] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(yyyy, datepart(yyyy,
      dateadd(weekday,1-datepart(weekday, @date),@date))-1900, 0)
    + dateadd(dy, datepart(dy,
      dateadd(weekday,1-datepart(weekday, @date),@date))-1,0)
END
GO

CREATE FUNCTION [dbo].[get_weekday_end] (@weekday tinyint,
                                 @date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(yyyy, datepart(yyyy,
      dateadd(weekday,@weekday-
      datepart(weekday, @date),@date))-1900, 0)
    + dateadd(ms, -3,
      dateadd(dy, datepart(dy,
      dateadd(weekday,@weekday-datepart(weekday, @date),
                                        @date)),0) )
END
GO

CREATE FUNCTION [dbo].[get_weekday_start] (@weekday tinyint,
                                   @date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(yyyy, datepart(yyyy,
      dateadd(weekday,@weekday-
      datepart(weekday, @date),@date))-1900, 0)
    + dateadd(dy, datepart(dy,
      dateadd(weekday,@weekday-datepart(weekday, @date),
                                        @date))-1,0)
END
GO

CREATE FUNCTION [dbo].[get_year_end] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
RETURN DATEADD(year, DATEDIFF(year, 0, GetDate())+1, 0)-1
END
GO

CREATE FUNCTION [dbo].[get_year_start] (@date datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   RETURN DATEADD(year,DATEDIFF(year,0, @date),0)
END
GO

CREATE FUNCTION [dbo].[get_yesterday_end] (@today datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   return dateadd(ms, -3, datediff(d,0,@today))
END
GO

CREATE FUNCTION [dbo].[get_yesterday_start] (@today datetime)
RETURNS datetime
WITH SCHEMABINDING, RETURNS NULL ON NULL INPUT
AS    BEGIN
   RETURN dateadd(day, -1, datediff(d,0,@today))
END
GO

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这些对我来说真的很有用,因为我在日期参数的报告服务中使用了它.您可以简单地创建一个引用此表函数的数据集,然后在RS中的任何日期时间的参数中使用这些数据集.

您可以像这样执行整个表值函数:

SELECT*FROM [MyDB].[dbo].[udfCommonDates](GetDate())

结果是这样的

在此输入图像描述

对于Reporting Services人员

现在我提到我之前使用这些来报告服务.现在RS人们可能在想,但这对我有何帮助,因为我需要一个数据集,而数据集只能基于存储过程或直接表.没问题创建以下存储过程:

CREATE PROCEDURE [dbo].[uspCommonDates] AS
begin
   set datefirst 1
   declare @date datetime
   set @date = getdate()
   select * from dbo.udfCommonDates(@date)
end

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现在您已经有了一个存储过程用作数据集......现在在报告服务中添加一个新数据集:

在此输入图像描述