Jas*_*ant 9 javascript jquery json
我有两个或更多的JavaScript对象.我想合并它们添加公共属性的值,然后按值的降序对它们进行排序.
例如
var a = {en : 5,fr: 3,in: 9}
var b = {en: 8,fr: 21,br: 8}
var c = merge(a,b)
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c 应该是这样的:
c = {
fr: 24,
en: 13,
in:9,
br:8
}
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即,两个对象都是合并的,添加了公共密钥的值,然后对密钥进行了排序.
这是我尝试过的:
var a = {en : 5,fr: 3,in: 9}
var b = {en: 8,fr: 21,br: 8}
c = {}
// copy common values and all values of a to c
for(var k in a){
if(typeof b[k] != 'undefined'){
c[k] = a[k] + b[k]
}
else{ c[k] = a[k]}
}
// copy remaining values of b (which were not common)
for(var k in b){
if(typeof c[k]== 'undefined'){
c[k] = b[k]
}
}
// Create a object array for sorting
var arr = [];
for(var k in c){
arr.push({lang:k,count:c[k]})
}
// Sort object array
arr.sort(function(a, b) {
return b.count - a.count;
})
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但我不认为它很好.如此多的循环:(如果有人可以提供更少杂乱和良好的代码将是很好的.
无法对对象的属性进行排序,但是可以对数组进行排序:
var merged = $.extend({}, a);
for (var prop in b) {
if (merged[prop]) merged[prop] += b[prop];
else merged[prop] = b[prop];
}
// Returning merged at this point will give you a merged object with properties summed, but not ordered.
var properties = [];
for (var prop in merged) {
properties.push({
name: prop,
value: merged[prop]
});
}
return properties.sort(function(nvp1, nvp2) {
return nvp1.value - nvp2.value;
});
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