将类似的函数组合成一个通用函数,包括将函数指针作为参数传递

Question

我试图将以下两个函数组合成一个便携函数:

void NeedleUSsim::FindIdxRho()
{
    searchTmp = &ninfo->rho;
    double *p = std::find_if(tplRho_deg, tplRho_deg+sampleDim[2], &NeedleUSsim::GreaterThanOrEqualTo);
    while(p != tplRho_deg+sampleDim[2])
    {
        idxRho = p - tplRho_deg;
        p = std::find_if(p+1, tplRho_deg+sampleDim[2], &NeedleUSsim::GreaterThanOrEqualTo);
    }
}

void NeedleUSsim::FindIdxDepth()
{
    searchTmp = &ninfo->l;
    double *p = std::find_if(tplL, tplL+sampleDim[1], &NeedleUSsim::LessThanOrEqualTo);
    while(p != tplL+sampleDim[1])
    {
        idxL = p - tplL;
        p = std::find_if(p+1, tplL+sampleDim[1], &NeedleUSsim::LessThanOrEqualTo);
    }
}

理想情况下,我希望函数的参数将tpl成员作为指针传递,并将大小和rho/l作为值传递.searchTmp是一个文件范围双精度指针.是否有任何简单的方法传递&NeedleUSsim :: GreaterThanOrEqualTo函数作为我正在尝试轻松编写的函数的参数？

提前感谢您的建议.

Answer 1

使代码更通用的最简单方法如下:

template<typename ComparisonType>
double* NeedleUSsim::FindIdx(double* containerBegin, double* containerEnd, ComparisonType comparison) {
    double* p = std::find_if(containerBegin, containerEnd, comparison);
    double* idx = 0;
    while(p != containerEnd)
    {
        idx = p - containerBegin;
        p = std::find_if(p+1, containerEnd, comparison);
    }
    return idx;
}

void NeedleUSsim::FindIdxRho()
{
  searchTmp = &ninfo->rho;
  double* idx = FindIdx(tplRho_deg, tplRho_deg+sampleDim[2], &NeedleUSsim::GreaterThanOrEqualTo);
  if( idx != 0 )
  {
    idxL = idx;
  }

}

void NeedleUSsim::FindIdxDepth()
{
  searchTmp = &ninfo->l;
  double* idx = FindIdx(tplL, tplL+sampleDim[1], &NeedleUSsim::LessThanOrEqualTo);
  if( idx != 0 )
  {
    idxRho = idx;
  }
}