IOS UIMenuController UIMenuItem,如何确定用通用选择器方法选择的项目

ort*_*t11 7 uimenucontroller ios

通过以下设置

....
MyUIMenuItem *someAction  = [[MyUIMenuItem alloc]initWithTitle : @"Something"  action : @selector(menuItemSelected:)];
MyUIMenuItem *someAction2 = [[MyUIMenuItem alloc]initWithTitle : @"Something2" action : @selector(menuItemSelected:)];
....

- (IBAction) menuItemSelected : (id) sender
{
    UIMenuController *mmi = (UIMenuController*) sender;
}
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如何确定选择了哪个菜单项.

并且不要说你需要有两种方法......提前谢谢.

sob*_*bri 15

好的,我已经解决了这个问题.解决方案并不漂亮,更好的选择是"Apple修复问题",但这至少有效.

首先,在UIMenuItem动作选择器前加上" magic_ ".并且不要制作相应的方法.(如果你能做到这一点,那么你无论如何都不需要这个解决方案).

我正在构建我的UIMenuItems:

NSArray *buttons = [NSArray arrayWithObjects:@"some", @"random", @"stuff", nil];
NSMutableArray *menuItems = [NSMutableArray array];
for (NSString *buttonText in buttons) {
    NSString *sel = [NSString stringWithFormat:@"magic_%@", buttonText];
    [menuItems addObject:[[UIMenuItem alloc] 
                         initWithTitle:buttonText
                         action:NSSelectorFromString(sel)]];
}
[UIMenuController sharedMenuController].menuItems = menuItems;
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现在,您的班级抓住按钮点击消息需要一些补充.(在我的例子中,该类是UITextField的子类.你的可能是其他东西.)

首先,我们一直希望拥有但不存在的方法:

- (void)tappedMenuItem:(NSString *)buttonText {
    NSLog(@"They tapped '%@'", buttonText);
}
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然后使方法成为可能:

- (BOOL)canPerformAction:(SEL)action withSender:(id)sender {
    NSString *sel = NSStringFromSelector(action);
    NSRange match = [sel rangeOfString:@"magic_"];
    if (match.location == 0) {
        return YES;
    }
    return NO;
}

- (NSMethodSignature *)methodSignatureForSelector:(SEL)sel {
    if ([super methodSignatureForSelector:sel]) {
        return [super methodSignatureForSelector:sel];
    }
    return [super methodSignatureForSelector:@selector(tappedMenuItem:)];
}

- (void)forwardInvocation:(NSInvocation *)invocation {
    NSString *sel = NSStringFromSelector([invocation selector]);
    NSRange match = [sel rangeOfString:@"magic_"];
    if (match.location == 0) {
        [self tappedMenuItem:[sel substringFromIndex:6]];
    } else {
        [super forwardInvocation:invocation];
    }
}
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  • 这是一个带有块支持的完整实现.https://github.com/steipete/PSMenuItem (4认同)