Ars*_*ray 246 c# post json httpwebrequest
这是我正在使用的代码:
// create a request
HttpWebRequest request = (HttpWebRequest)
WebRequest.Create(url); request.KeepAlive = false;
request.ProtocolVersion = HttpVersion.Version10;
request.Method = "POST";
// turn our request string into a byte stream
byte[] postBytes = Encoding.UTF8.GetBytes(json);
// this is important - make sure you specify type this way
request.ContentType = "application/json; charset=UTF-8";
request.Accept = "application/json";
request.ContentLength = postBytes.Length;
request.CookieContainer = Cookies;
request.UserAgent = currentUserAgent;
Stream requestStream = request.GetRequestStream();
// now send it
requestStream.Write(postBytes, 0, postBytes.Length);
requestStream.Close();
// grab te response and print it out to the console along with the status code
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
string result;
using (StreamReader rdr = new StreamReader(response.GetResponseStream()))
{
result = rdr.ReadToEnd();
}
return result;
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当我运行它时,我总是得到500内部服务器错误.
我究竟做错了什么?
小智 367
我这样做并且正在工作的方式是:
var httpWebRequest = (HttpWebRequest)WebRequest.Create("http://url");
httpWebRequest.ContentType = "application/json";
httpWebRequest.Method = "POST";
using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))
{
string json = "{\"user\":\"test\"," +
"\"password\":\"bla\"}";
streamWriter.Write(json);
}
var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
{
var result = streamReader.ReadToEnd();
}
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我写了一个库来以更简单的方式执行这个任务,它在这里:https://github.com/ademargomes/JsonRequest
希望能帮助到你.
Sea*_*son 140
ADEMAR的溶液可以通过利用来改善JavaScriptSerializer
的Serialize
方法来提供该对象的JSON隐式转换.
此外,可以利用using
语句的默认功能,以省略显式调用Flush
和Close
.
var httpWebRequest = (HttpWebRequest)WebRequest.Create("http://url");
httpWebRequest.ContentType = "application/json";
httpWebRequest.Method = "POST";
using (var streamWriter = new StreamWriter(httpWebRequest.GetRequestStream()))
{
string json = new JavaScriptSerializer().Serialize(new
{
user = "Foo",
password = "Baz"
});
streamWriter.Write(json);
}
var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse();
using (var streamReader = new StreamReader(httpResponse.GetResponseStream()))
{
var result = streamReader.ReadToEnd();
}
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NtF*_*reX 42
该HttpClient
类型是比WebClient
和更新的实现HttpWebRequest
.
您只需使用以下行.
string myJson = "{'Username': 'myusername','Password':'pass'}";
using (var client = new HttpClient())
{
var response = await client.PostAsync(
"http://yourUrl",
new StringContent(myJson, Encoding.UTF8, "application/json"));
}
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当您需要HttpClient
多次时,建议仅创建一个实例并重复使用或使用新实例HttpClientFactory
.
Dav*_*rke 31
继Sean的帖子之后,没有必要嵌套using语句.通过using
StreamWriter,它将在块的末尾被刷新和关闭,因此不需要显式调用Flush()
和Close()
方法:
var request = (HttpWebRequest)WebRequest.Create("http://url");
request.ContentType = "application/json";
request.Method = "POST";
using (var streamWriter = new StreamWriter(request.GetRequestStream()))
{
string json = new JavaScriptSerializer().Serialize(new
{
user = "Foo",
password = "Baz"
});
streamWriter.Write(json);
}
var response = (HttpWebResponse)request.GetResponse();
using (var streamReader = new StreamReader(response.GetResponseStream()))
{
var result = streamReader.ReadToEnd();
}
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Viv*_*ara 12
如果需要异步调用则使用
var request = HttpWebRequest.Create("http://www.maplegraphservices.com/tokkri/webservices/updateProfile.php?oldEmailID=" + App.currentUser.email) as HttpWebRequest;
request.Method = "POST";
request.ContentType = "text/json";
request.BeginGetRequestStream(new AsyncCallback(GetRequestStreamCallback), request);
private void GetRequestStreamCallback(IAsyncResult asynchronousResult)
{
HttpWebRequest request = (HttpWebRequest)asynchronousResult.AsyncState;
// End the stream request operation
Stream postStream = request.EndGetRequestStream(asynchronousResult);
// Create the post data
string postData = JsonConvert.SerializeObject(edit).ToString();
byte[] byteArray = Encoding.UTF8.GetBytes(postData);
postStream.Write(byteArray, 0, byteArray.Length);
postStream.Close();
//Start the web request
request.BeginGetResponse(new AsyncCallback(GetResponceStreamCallback), request);
}
void GetResponceStreamCallback(IAsyncResult callbackResult)
{
HttpWebRequest request = (HttpWebRequest)callbackResult.AsyncState;
HttpWebResponse response = (HttpWebResponse)request.EndGetResponse(callbackResult);
using (StreamReader httpWebStreamReader = new StreamReader(response.GetResponseStream()))
{
string result = httpWebStreamReader.ReadToEnd();
stat.Text = result;
}
}
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Dus*_*tin 11
我最近提出了一种更简单的发布JSON的方法,还有从我的应用程序中的模型转换的额外步骤.请注意,您必须为控制器创建模型[JsonObject]以获取值并进行转换.
请求:
var model = new MyModel();
using (var client = new HttpClient())
{
var uri = new Uri("XXXXXXXXX");
var json = new JavaScriptSerializer().Serialize(model);
var stringContent = new StringContent(json, Encoding.UTF8, "application/json");
var response = await Client.PutAsync(uri,stringContent).Result;
...
...
}
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模型:
[JsonObject]
[Serializable]
public class MyModel
{
public Decimal Value { get; set; }
public string Project { get; set; }
public string FilePath { get; set; }
public string FileName { get; set; }
}
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服务器端:
[HttpPut]
public async Task<HttpResponseMessage> PutApi([FromBody]MyModel model)
{
...
...
}
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警告!我对这个问题有非常强烈的看法。
.NET 现有的 Web 客户端对开发人员不友好! WebRequest和WebClient是“如何挫败开发人员”的主要示例。它们冗长而复杂;当您只想在 C# 中执行一个简单的 Post 请求时。HttpClient在某种程度上解决了这些问题,但它仍然不足。最重要的是,微软的文档很糟糕……真的很糟糕;除非你想筛选一页又一页的技术简介。
开源来拯救。有三个优秀的开源免费 NuGet 库作为替代。谢天谢地!这些都得到了很好的支持,记录在案,是的,很容易 - 更正......超级容易 - 使用。
它们之间没有太多关系,但我会给 ServiceStack.Text 一点优势……
好的 - 那么 ServiceStack.Text 中的 JSON 格式的 Post 请求是什么样的?
var response = "http://example.org/login"
.PostJsonToUrl(new Login { Username="admin", Password="mypassword" });
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那是一行代码。简洁大方!将上述内容与 .NET 的 Http 库进行比较。
未提及此选项:
using (var client = new HttpClient())
{
client.BaseAddress = new Uri("http://localhost:9000/");
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
var foo = new User
{
user = "Foo",
password = "Baz"
}
await client.PostAsJsonAsync("users/add", foo);
}
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实现此目的的一些不同且干净的方法是使用 HttpClient 像这样:
public async Task<HttpResponseMessage> PostResult(string url, ResultObject resultObject)
{
using (var client = new HttpClient())
{
HttpResponseMessage response = new HttpResponseMessage();
try
{
response = await client.PostAsJsonAsync(url, resultObject);
}
catch (Exception ex)
{
throw ex
}
return response;
}
}
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