PDO使用PDO :: FETCH_PROPS_LATE和__construct()调用？

Question

我正在尝试使用PHP PDO 创建一个新的Setting对象调用__construct()方法实例并约束PDO :: FETCH_PROPS_LATE.不幸的是,我收到了这个警告(并且绑定不起作用).

如何将列值传递给构造函数方法？

警告:在pdo.php中缺少Setting :: __ construct()的参数1.

注意:未定义的变量:pdo.php中的键.

class Setting
{

    protected $key, $value, $displayable;

    public function __construct($key, $value = null, $displayable = 1)
    {
        $this->key         = $key;
        $this->value       = $value;
        $this->displayable = $displayable > 0;
    }

}

while($mashup = current($mashups))
{
    $stmt = $dbh->prepare('SELECT `key`, value, displayable
        FROM setting WHERE mashup_id = :id');

    $stmt->bindParam(':id', $mashup->id, PDO::PARAM_INT);
    $stmt->execute();

    $settings = $stmt->fetchAll(PDO::FETCH_CLASS|PDO::FETCH_PROPS_LATE,
       'Setting');
}

$stmt->closeCursor();

Answer 1

您$key的构造函数中有一个非默认参数:

public function __construct($key, $value = null, $displayable = 1)

所以,当你这样做时:

$settings = $stmt->fetchAll(PDO::FETCH_CLASS|PDO::FETCH_PROPS_LATE,'Setting');

错误:warning: Missing argument 1 for Setting::__construct() in pdo.php仅针对参数抛出,$key因为它不是默认值.

正确使用fetchAll(PDO::FETCH_CLASS|PDO::FETCH_PROPS_LATE,... 是这样的:

$variable = $stmt->fetchAll(PDO::FETCH_CLASS|PDO::FETCH_PROPS_LATE,
                           'classname', 
                            <array of parameter names(in order) used in constructor>);

所以,在你的情况下:

$variable = $stmt->fetchAll(PDO::FETCH_CLASS|PDO::FETCH_PROPS_LATE,
                            'Setting', 
                             array('key', 'value', 'displayable');