如何从模板函数返回布尔值？

Question

在下面的C++代码中,我想使用模板函数来确定两个向量是否完全相同,但是,我总是从模板函数中得到错误.你能给我一些关于如何从模板函数返回布尔值的建议吗？(我的C++编译器是g ++ 4.6)

编辑:在pop_back p1 p2 p3 p4之后,结果现在与我的预期相匹配.

#include <iostream>
#include <memory>
#include <vector>

using namespace std;

template<class T> bool areTheyMatched(shared_ptr<vector<T>> p1, shared_ptr<vector<T>> p2) {
if ((*p1).size() == (*p2).size()) {
    cout << (*p1).size() << endl;
    for (unsigned int i = 0;  i < (*p1).size(); i++) {
      if ((*p1)[i] != (*p2)[i]) {
        cout << (*p1)[i] << " " <<  (*p2)[i] << endl;   
        return false;
          } 
        }
 } else {
    return false;
 }
 cout << "All elements are exactly the same" << endl;
 return true;
 }


 int main(int argc, char *argv[]) {
   shared_ptr<vector<int>> p1(new vector<int>);
   shared_ptr<vector<int>> p2(new vector<int>);
   shared_ptr<vector<double>> p3(new vector<double>);
   shared_ptr<vector<double>> p4(new vector<double>);
   for (int i = 0; i < 10; i++) 
     (*p1).push_back(i); 
   for (int i = 0; i < 9; i++) 
     (*p2).push_back(i);
   (*p2).push_back(11);
   for (double i = 0.0; i < 9.9; i += 1.1) 
      (*p3).push_back(i);
   for (double i = 0.0; i < 8.8; i += 1.1) 
      (*p4).push_back(i);
   (*p4).push_back(11.0);
   cout << "Case 1: " << areTheyMatched(p1, p2) << endl;
   (*p1).pop_back();
   (*p2).pop_back();
   cout << "Case 2: " << areTheyMatched(p1, p2) << endl;
   cout << "Case 3: " << areTheyMatched(p3, p4) << endl;
   (*p3).pop_back();
   (*p4).pop_back();
   cout << "Case 4: " << areTheyMatched(p3, p4) << endl;
   p1.reset();
   p2.reset();
   p3.reset();
   p4.reset();
   return 0;
}

Answer 1

模板代码似乎很好,但测试向量从来都不一样,是不是.

首先,它们中的一个具有元件11,并且当移除它们时它们具有不同的尺寸.