san*_*lto 2 mysql sql relational-division sql-match-all
假设它是一个销售照相机的网站.这是我的实体(表格):
Camera: A simple camera
Feature: A feature like: 6mp, max resolution 1024x768,
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事情是相机和功能之间我有多对多的关系,所以我有一个额外的表:
camera -> cameras_features -> feature
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所以,查询很简单:
如何获得具有1,2和3功能的所有相机?
这就像构建位图索引一样.
您可以用来测试解决方案是否正常的数据
C1 has features 1,2,3
C2 has features 1,2,4
C3 has features 1,2
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以下是查询和预期结果:
这是我做的(它的工作原理,但它真的很难看,不想使用它):
SELECT * FROM camera c
WHERE c.id IN (
(SELECT c.id FROM camera c JOIN cameras_features f ON (c.id=f.camera_id)
WHERE f.feature_id=1)
q1 JOIN -- simple intersect
(SELECT c.id FROM camera c JOIN cameras_features f ON (c.id=f.camera_id)
WHERE f.feature_id=2)
q2 JOIN ON (q1.id=q2.id)
)
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SELECT camera.id
FROM camera JOIN camera_features ON camera.id=camera_features.camera_id
GROUP BY camera.id
HAVING sum(camera_features.feature_id IN (1,2,3))=3
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3是的功能数量(1,2,3).假设(camera_id,feature_id)是独一无二的camera_features.
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