如何将参数传递给C#中的公共类?

mmc*_*ynn 2 .net c# arguments console-application

如何将参数传递给C#中的公共类.我是C#的新手,所以请原谅n00b问题.

鉴于此示例类:

public class DoSomething
{
    public static void  Main(System.String[] args)
    {

        System.String apple = args[0];
        System.String orange = args[1];
        System.String banana = args[2];
        System.String peach = args[3];

        // do something
    }
}
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如何传递请求的参数?

我希望写下这样的东西:

DoSomething ds = new DoSomething();
ds.apple = "pie";
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但这失败了.

Cod*_*ome 6

首先,让我们用笔记点击你的版本,然后继续你想要的.

// Here you declare your DoSomething class
public class DoSomething
{
    // now you're defining a static function called Main
    // This function isn't associated with any specific instance
    // of your class. You can invoke it just from the type,
    // like: DoSomething.Main(...)
    public static void Main(System.String[] args)
    {
        // Here, you declare some variables that are only in scope
        // during the Main function, and assign them values 
        System.String apple = args[0];
        System.String orange = args[1];
        System.String banana = args[2];
        System.String peach = args[3];
    }
        // at this point, the fruit variables are all out of scope - they
        // aren't members of your class, just variables in this function.

    // There are no variables out here in your class definition
    // There isn't a constructor for your class, so only the
    // default public one is available: DoSomething()
}
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以下是您可能想要的类定义:

public class DoSomething
{
    // The properties of the class.
    public string Apple; 
    public string Orange;

    // A constructor with no parameters
    public DoSomething()
    {
    }

    // A constructor that takes parameter to set the properties
    public DoSomething(string apple, string orange)
    {
        Apple = apple;
        Orange = orange;
    }

}
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然后你就可以创建/操作类,如下所示.在每种情况下,实例最终将以Apple ="foo"和Orange ="bar"结束

DoSomething X = new DoSomething("foo", "bar");

DoSomething Y = new DoSomething();
Y.Apple = "foo";
Y.Orange = "bar";

DoSomething Z = new DoSomething()
{
    Apple = "foo",
    Orange = "bar"
};
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dav*_*ooh 5

通过命令行启动应用程序时String[] args,将Main填充方法的参数:

/your/application/path/DoSomething.exe arg1 arg2 arg3 ...

如果要以编程方式传递这些参数,则必须将变量设置为public Properties,例如:

public class DoSomething
{
   public string Apple { get; set; }
   public string Orange { get; set; }
   public string Banana { get; set; }
   // other fruits...
}
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然后,您可以执行以下操作:

public class Test
{
    public static void  Main(System.String[] args)
    {
        DoSomething ds = new DoSomething();
        ds.Apple = "pie";

        // do something
    }
}
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