Uto*_*025 86 sms android broadcastreceiver android-service
我想在一个BroadcastReceiver内部启动Service.我想要做的是有一个后台运行service,收集传入的短信,并记录来电.我认为最好的解决方法是service运行一个包含可以编目的广播接收器.
我该怎么做呢?我已经启动并运行了我的服务.
waq*_*lam 120
由于您的服务已经设置,只需在您的服务中添加广播接收器:
private final BroadcastReceiver receiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
String action = intent.getAction();
if(action.equals("android.provider.Telephony.SMS_RECEIVED")){
//action for sms received
}
else if(action.equals(android.telephony.TelephonyManager.ACTION_PHONE_STATE_CHANGED)){
//action for phone state changed
}
}
};
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在你的服务中onCreate这样做:
IntentFilter filter = new IntentFilter();
filter.addAction("android.provider.Telephony.SMS_RECEIVED");
filter.addAction(android.telephony.TelephonyManager.ACTION_PHONE_STATE_CHANGED);
filter.addAction("your_action_strings"); //further more
filter.addAction("your_action_strings"); //further more
registerReceiver(receiver, filter);
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在你的服务中onDestroy:
unregisterReceiver(receiver);
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而且你很高兴能够接收你提到过的过滤广播onCreate.如果需要,请务必添加任何权限.例如
<uses-permission android:name="android.permission.RECEIVE_SMS" />
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Pau*_*rke 23
更好的模式是创建一个独立的模式BroadcastReceiver.这可以确保您的应用可以响应广播,无论广播是否Service正在运行.实际上,使用这种模式可以Service完全不需要持续运行.
BroadcastReceiver在Manifest中注册,并为其创建单独的类/文件.
例如:
<receiver android:name=".FooReceiver" >
<intent-filter >
<action android:name="android.provider.Telephony.SMS_RECEIVED" />
</intent-filter>
</receiver>
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当接收器运行时,你只需将一个Intent(Bundle)传递给Service,并在其中响应onStartCommand().
例如:
public class FooReceiver extends BroadcastReceiver {
@Override
public void onReceive(Context context, Intent intent) {
// do your work quickly!
// then call context.startService();
}
}
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