MS Access:WHERE-EXISTS子句不能处理视图?

Ale*_*ler 8 sql database ms-access select sql-view

先决条件:在MS Access 2010中,创建以下表:

CREATE TABLE ATBL(ID INT);
INSERT INTO ATBL(ID) VALUES (1);
INSERT INTO ATBL(ID) VALUES (2);
INSERT INTO ATBL(ID) VALUES (3);

CREATE TABLE BTBL(ID INT);
INSERT INTO BTBL(ID) VALUES (1);
INSERT INTO BTBL(ID) VALUES (2);
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还要创建一个名为BVIEW的视图,它使用以下SELECT语句:

SELECT A.ID FROM ATBL AS A WHERE A.ID = 1 OR A.ID = 2
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现在BVIEW应该具有与BTBL相同的内容.然而,以下两个查询将返回不同的结果:

SELECT A.ID FROM ATBL AS A WHERE EXISTS (SELECT 1 FROM  BTBL AS B WHERE B.ID=A.ID)
SELECT A.ID FROM ATBL AS A WHERE EXISTS (SELECT 1 FROM BVIEW AS B WHERE B.ID=A.ID)
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第一个查询返回两个记录(1和2),但第二个查询返回ATBL的所有记录.这有什么不对?我错过了什么吗?

Gan*_*nus 6

视图实际上是一个保存的SQL SELECT语句.至少,这是MS Access中保存的视图.你使用相同的内部变量A和B.恕我直言,他们正在混合.最后一行真的看起来像

SELECT A.ID FROM ATBL AS A WHERE EXISTS (SELECT 1 FROM (SELECT A.ID FROM ATBL AS A WHERE A.ID = 1 OR A.ID = 2) AS B WHERE B.ID=A.ID)
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尝试更改一些内部名称,例如:

SELECT AA.ID FROM ATBL AS AA WHERE AA.ID = 1 OR AA.ID = 2
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所以,最后一行看起来像

SELECT A.ID FROM ATBL AS A WHERE EXISTS (SELECT 1 FROM (SELECT AA.ID FROM ATBL AS AA WHERE AA.ID = 1 OR AA.ID = 2) AS B WHERE B.ID=A.ID)
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所以,正如我们在这里看到的,MS Access甚至不知道如何隔离别名!

  • 真的太可怕了,不是吗?MS Access甚至不知道隔离内部变量! (2认同)